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mart [117]
3 years ago
11

What is the least important factor of a personal fitness program?

Health
1 answer:
faust18 [17]3 years ago
5 0

Answer:

The time of day

Explanation:

Although there are many important factors that need to be taken into account when planning and executing an exercise program, for you or another person, the least important factor to take into account is <u>the time of day</u> in which it is decided to perform the planned exercises.

Although, it is still extremely important to take time for sleep, so it is not a problem to perform an exercise program at night, however it should not affect your sleep patterns.

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Which of the following BEST describes a body in equilibrium?
sukhopar [10]

\textsf {\large{\underline { \underline {SOLUTION:-}}}}

⇰Let O be the point of observation on the ground OX.

⇰Let A and B be the two positions of the jet.

\bf➠Then, \angle XOA=60⁰ \: and   \: \angle \: XOB=30⁰ \\  \\

\bf ➠Draw \:   AL \perp \: OX \: and  \: BM \perp \: OX \\  \\

\bf \:⇰ Let \: AL=BM=h \: meters. \\  \\

\bf \: ⇰ \: Speed \: of \: Jet  = 720 \: km/hr\\

\bf =  \huge( \small \: 720 \times  \frac{5}{18}  \huge) \small \: m / s\\

\bf = 200 \: m/s

\bf \:➥ Time  \: taken \: to \: cover \: the \: distance  \: AB=15  \: sec  \\  \\

\bf➥ Distance  \: covered =(speed×time) \\  \\

\:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \bf = (200 \times 15)m = 3000m \\  \\

\bf \therefore LM=AB=3000m \\  \\

{ \bf \: ⇰  \: Let \: OL} = x   \:  \bf m \\  \\

\bf➥From  \: right  \: \triangle OLA, \: we \: have: \\

\bf \frac{OL}{AL} =cot \: 60⁰= \frac{1}{ \sqrt{3} } \implies \frac{x}{h}  =  \frac{1}{ \sqrt{3} }  \\  \\

\bf \implies \: x =  \frac{h}{ \sqrt{3} }  \:  \:  \:  \:  \:  \:  \: ....(1) \\  \\

\bf \:➥ From  \: right  \: \triangle \: OMB,we \: have: \\

\bf\frac{OM}{BM} =cot30⁰= \sqrt{3}  \\  \\

\bf \implies \:  \frac{x + 3000}{h}  =  \sqrt{3}  \\  \\

\bf[ \boxed{➯OM=OL+LM=OL+AB=(x+3000)m  \: and \: BM=h \: m]}

\bf \implies \: x + 3000 =  \sqrt{3} h \\

\bf \implies \: x = ( \sqrt{3} h - 3000) \:  \:  \:  \:  \:  \: ....(2) \\

⇰ Equating the value of x from (1) and (2),we get;

\bf \:  \sqrt{3} h - 3000  =  \frac{h}{ \sqrt{3} }  \\  \\

\implies \bf \: 3h  - 3000 \sqrt{3}  = h \\

\bf \implies \: 2h = (3000 \times  \sqrt{3} ) = (3000 \times 1.762) \\

\bf \implies \: h = (3000 \times 0.866) = 2598  \\  \\

\bf \:➥ Hence \: ,the \: required  \: height \: is \: \boxed{ \boxed{ \bf2598 \: m.}} \\  \\

☆To View full answer drag your screen ⇰

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2 years ago
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