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miss Akunina [59]
3 years ago
6

6x + 1 = 2(3x - 2) + 5 A) x = 0 B) x = 12 C) x = 1 12 D) infinitely many solutions

Mathematics
2 answers:
wlad13 [49]3 years ago
5 0

6x + 1 = 2(3x - 2) + 5

6x + 1 = 6x - 4 + 5

6x + 1 = 6x + 1

6x = 6x

x = x

D.) Infinitely many solutions

Alex17521 [72]3 years ago
3 0

Answer:

D) infinitely many solutions

Step-by-step explanation:

6x + 1 = 2(3x - 2) + 5

Distribute

6x+1 = 6x -4+5

Combine like terms

6x+1 = 6x+1

Subtract 6x from each side

6x-6x+1 = 6x-6x+1

1=1

This is always true, so x has infinite solutions

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What to do if quadratic equation has a negative spuare root?
alex41 [277]

If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 3+\sqrt{5}

then 3-\sqrt{5} will also be a solution.

3 0
3 years ago
Which equation is the inverse of 2(x - 2)2 = 8(7 + y)?
Marina86 [1]

Answer:

The inverse of 2(x - 2)^2 = 8(7 + y) is y=\sqrt{(4x+28)}+2

Step-by-step explanation:

Given equation :2(x - 2)^2 = 8(7 + y)

\Rightarrow \frac{2(x-2)^2}{8}=7+y\\\Rightarrow \frac{2(x-2)^2}{8}-7=y

Replace x with y and y with x

So, \Rightarrow \frac{2(y-2)^2}{8}-7=x\\\Rightarrow \frac{2(y-2)^2}{8}=x+7\\\Rightarrow 2(y-2)^2=8(x+7)\\\Rightarrow (y-2)^2=4(x+7)\\\Rightarrow (y-2)=\sqrt{4(x+7)}\\\Rightarrow y=\sqrt{4(x+7)}+2\\\Rightarrow y=\sqrt{4x+28)}+2

So, Option C is correct

Hence The inverse of 2(x - 2)^2 = 8(7 + y) is y=\sqrt{(4x+28)}+2

4 0
3 years ago
Mona solved an equation incorrectly, as shown below:
CaHeK987 [17]
Mona subtracted 5 where she should have divided 5. If the equasion was. x+5=30 then she would have subtracted 5.
3 0
3 years ago
Read 2 more answers
Find y.<br><br> A. 42–√<br> B. 4<br> C. 22–√<br> D. 83√3
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Answer:

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6 0
2 years ago
a costumer buys 17.01 in gas and requests one five dollar ticket, two one dollar tickets, and one three dollar ticket. he gives
marin [14]

The customer gives you:
-- a  ticket worth . . . . . . 5
-- a ticket worth. . . . . . . 2
-- a bill. . . . . . . . . . . . 100
               ------------------------
-- Total. . . . . . . . . . . . 107

You give the customer:
-- gas worth . . . . . . . . 17.01               
-- a ticket worth . . . . . . 5
-- two $1 tickets worth . 2
-- a ticket worth . . . . . . 3
            ------------------------------
-- Total . . . . . . . . . . . . 27.01

In order to make the trade even, you owe the customer

                               (107.00  -  27.01)  =  <em>$79.99 more
</em>
<em>
</em>You could give it to him in the form of some combination of magazines,
soda, cigarettes, gum, newspapers, motor oil, car deodorizers, candy
bars, washer fluid, anti-freeze, etc.  But he'd be there all day trying to
decide what he wants and making it all add up to exactly $79.99, and
there's a long line of other customers waiting behind him.

That's the beauty of cash money.  You can count out exactly the proper
amount, it only takes a few seconds and bada-bing, he's out of there and
back on the road.

8 0
3 years ago
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