3 years ago

6x + 1 = 2(3x - 2) + 5 A) x = 0 B) x = 12 C) x = 1 12 D) infinitely many solutions

Mathematics

2 answers:

wlad13 [49]3 years ago

5 0

6x + 1 = 2(3x - 2) + 5

6x + 1 = 6x - 4 + 5

6x + 1 = 6x + 1

6x = 6x

x = x

D.) Infinitely many solutions

Alex17521 [72]3 years ago

3 0

Answer:

D) infinitely many solutions

Step-by-step explanation:

6x + 1 = 2(3x - 2) + 5

Distribute

6x+1 = 6x -4+5

Combine like terms

6x+1 = 6x+1

Subtract 6x from each side

6x-6x+1 = 6x-6x+1

1=1

This is always true, so x has infinite solutions

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