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4 years ago

6

What is 20% off 123.74?

1 answer:

Marina CMI [18]4 years ago

8 0

20% of 123.74 can be represented like so:

123.74 * (20/100)

Which is

123.74 * (1/5)

Which is

123.74 ÷ 5

Which equals your answer,

24.748

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Coach Kent brings 3 quarts of sports drink to soccer practice. He gives the same amount of the drink to each of his 16 players.

Delvig [45]

The answer is 48 ounces
Your welcome

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4 years ago

In order to solve the following system of equations by elimination, which process creates opposite coefficients to eliminate the

leonid [27]

Answer:

C. Multiply the first equation by -4

Step-by-step explanation:

Hi there!

In order to eliminate the y values, we would have to find a number in which the sum of the top y value and the bottom y value would equal 0. In this case, the bottom y value is equal to +4 (the +4y), so we would have to find the number that would add to make that 0, which is -4. Since the y value for the top equation is 1, all we have to do is multiply the equation by -4 so that our y value is equal to -4y and the y can be eliminated.

I hope this helps!!

7 0

3 years ago

The expression (secx + tanx)2 is the same as _____.

trapecia [35]

<u>Answer:</u>

The expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

<u>Solution:</u>

From question, given that $\bold{(\sec x+\tan x)^{2}}$

By using the trigonometric identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$ the above equation becomes,

$(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x$

We know that $\sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}$

$(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

$=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

On simplication we get

$=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}$

By using the trigonometric identity $\cos ^{2} x=1-\sin ^{2} x$ ,the above equation becomes

$=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}$

By using the trigonometric identity $(a+b)^{2}=a^{2}+2ab+b^{2}$

we get $1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}$

$=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}$

$=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}$

By using the trigonometric identity $a^{2}-b^{2}=(a+b)(a-b)$ we get $1-\sin ^{2} x=(1+\sin x)(1-\sin x)$

$=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}$

$= \frac{1+\sin x}{1-\sin x}$

Hence the expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

8 0

3 years ago

Tiffany was helping her mom cook if they started at 2:30 and it took 2 hours and 45 minutes what time will it be done?

DIA [1.3K]

Answer:5:15

Step-by-step explanation:

2:30+2 hour=4:30

4:30+45=5:15

5 0

2 years ago

Hurrrry Pleeasssseee<br> Find the value of In(-7).

murzikaleks [220]

Answer:

The value of in(-7) or (-7) is really just -7 I think

Step-by-step explanation:

sorry if wrong

3 0

3 years ago