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Advocard [28]
4 years ago
11

Complete these brønsted-lowry reaction hpo42- + f-

Chemistry
2 answers:
Inessa05 [86]4 years ago
5 0

Answer : The reaction is,

HPO^{2-}_4+F^-\rightarrow HF+PO^{2-}_4

Explanation :

The complete bronsted-lowry reaction is,

HPO^{2-}_4+F^-\rightarrow HF+PO^{2-}_4

Bronsted-lowry reaction : It is an acid-base reaction in which a proton is transferred from an acid to base. That means acid donates protons and base accept protons.

In the given reaction, HPO^{2-}_4 donates a proton to F^- and they form HF as an acid and PO^{2-}_4 as base.

goldenfox [79]4 years ago
4 0

Answer : The brønsted-lowry reaction is,

HPO^{2-}_4+F^-\rightarrow HF+PO^{3-}_4

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

The complete bronsted-lowry reaction is,

HPO^{2-}_4+F^-\rightarrow HF+PO^{3-}_4

In the given reaction, HPO^{2-}_4 donates a proton or hydrogen to F^- and they form HF as an acid and PO^{3-}_4 as base.

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2 years ago
A compound containing chromium, Cr; chlorine, Cl; and oxygen, O, is analyzed and found to be 33.6% chromium, 45.8% chlorine, and
Assoli18 [71]

Answer

The empirical formula is CrO₂Cl₂

Explanation:

Empirical formula is the simplest whole number ratio of an atom present in a compound.

The compound contain, Chromium=33.6%

                                         Chlorine=45.8%

                                          Oxygen=20.6%

And the molar mass of Chromium(Cr)=51.996 g mol.

                 Chlorine containing molar mass (Cl)= 35.45    g mol.

                 Oxygen containing molar mass (O)=15.999  g mol.

Step-1

 Then,we will get,

Cr=\frac{1}{51.996} \times33.6=0.64 mol

Cl= \frac{1}{35.45} \times45.8=1.29 mol.

O=\frac{1}{15.99} \times=1.28 mol.

Step-2

Divide the mole value with the smallest number of mole, we will get,

Cr= \frac{0.64}{0.64} =1

Cl= \frac{1.29}{0.64} =2

O= \frac{1.28}{0.64} =2

Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)

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4 years ago
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