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Aleksandr-060686 [28]
3 years ago
9

What are the products of the light reactions?

Chemistry
2 answers:
max2010maxim [7]3 years ago
8 0
During these initial reactions, water is used and oxygen<span> is released. The energy from sunlight is converted into a small amount of </span>ATP<span> and an energy carrier called </span>NADPH<span>. Together with </span>carbon dioxide<span>, these are used to make </span>glucose<span> (</span>sugar<span>) through a process called the Calvin Cycle.</span>
Anna [14]3 years ago
4 0

Answer:

ATP, NADPH and oxygen are the products of light reaction.

Explanation:

Light reaction occurs in the presence of sunlight and is the first phase of photosynthesis reaction. Chlorophyll molecule absorbs the energy from the sunlight and later uses in the formation of ATP and NADPH.

The water is used up during the reaction. The light energy is used to obtain ATP, NADPH and oxygen. These products of light reaction are used further by plants during dark reaction of photosynthesis.

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Explanation:

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How many grams of chlorine gas are present in a 150. liter cylinder of chlorine held at a pressure of 1.00 atm and 0. °C? Group
OlgaM077 [116]

Answer:

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 1.00 atm
  • V= 150 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
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Replacing:

1.00 atm* 150 L= n*0.08206 \frac{atm*L}{mol*K} *273 K

Solving:

n=\frac{1.00 atm* 150 L}{0.08206 \frac{atm*L}{mol*K}*273 K}

n= 6.69 moles

Being Cl= 35.45 g/mole, the molar mass of chlorine gas is:

Cl₂=2*35.45 g/mole= 70.9 g/mole

So if 1 mole has 70.9 grams, 6.69 moles of the gas, how much mass does it have?

mass=\frac{6.69 moles*70.9 grams}{1 mole}

mass= 474.321 grams ≅ 474 grams

<u><em>474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C</em></u>

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