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3 years ago

If you burn 29.4 g of hydrogen and produce 263 g of water, how much oxygen reacted?

Chemistry

1 answer:

vovikov84 [41]3 years ago

7 0

The reaction between hydrogen and oxygen to form water is given as:

$H_2 + O_2 \rightarrow H_2O$

The balanced reaction is:

$2H_2 + O_2 \rightarrow 2H_2O$

According to the balanced reaction,

4 g of hydrogen ( $4\times 1$ ) reacts with 32 g of oxygen ( $2\times 16$ ).

So, oxygen reacted with 29.4 g of hydrogen is:

$\frac{29.4\times 32}{4} = 235.2 g$

Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.

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Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron falls from the n = 7 to the n

Gre4nikov [31]

Answer:

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

Explanation:

The energy of nth energy levels of the H atom is given as:

$E_n = -2.18 \times 10^{-18} \times \frac{1}{n^2} J$

Energy of the seventh energy level = $E_7$

$E_7=-2.18 \times 10^{-18} \times \frac{1}{7^2} J$

$E_7=-2.18 \times 10^{-18} \times \frac{1}{7^2} J=-4.4490\times 10^{-20} J$

Energy of the seventh energy level = $E_4$

$E_4=-2.18 \times 10^{-18} \times \frac{1}{4^2} J$

$E_4=-2.18 \times 10^{-18} \times \frac{1}{16} J=-1.3625\times 10^{-19} J$

Energy of the light emitted will be equal to the energy difference of the both levels.

$E=E_7-E_4=-4.4490\times 10^{-20} J-(-1.3625\times 10^{-19} J)$

$E=9.176\times 10^{-20} J$

Wavelength corresponding to energy E can be calculated by using Planck's equation:

$E=\frac{hc}{\lambda }$

$\lambda =\frac{hc}{E}=\frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{9.176\times 10^{-20} J}=2.166\times 10^{-6} m=2166 nm$

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

8 0

2 years ago

What are the four important steps needed to obtain accurate melting points on a mel-temp

AveGali [126]

Explanation:

1) refine the specimen into fine powder 2) place the smallest amount you can see in the capillary tube 3) set the voltage to increase exponentially to 200 below the predicted temperature, then adjust so that the temperature rises to 20 per minute 4) report the temperature at which the liquid first appears and the temperature at which the last crystal disappears.

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3 years ago

Let’s say that you have a solvatochromic compound that appears red in a solvent. You dissolve the compound in another solvent an

KiRa [710]

Answer:

Hypsochromic shift.

The second solvent is more polar.

Explanation:

Compound A + Solvent 1 = red

Compound A + Solvent 2 = orange

Since orange has a smaller wavelength than red, the electronic transition observed when the compound A is dissolved in solvent 2 has a higher energy.

A band transition to a lower wavelength and higher energy is called a hypsochromic shift.

The change in the color due to the solvent is called solvatochromism. Usually, when the hypsochromic shift is observed (negative solvatochromism) it means that the solvent is more polar.

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2 years ago

Flammable materials like alcohol should never be dispensed or used near True or False

galben [10]

near what like open flames? if so false unless it clarifies the solution requires alcohol then its a no go

7 0

3 years ago

Element m reacts with fluorine to form an ionic compound with the formula mf4. the m cation has 18 electrons. element m is:____.

polet [3.4K]

Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

<h3>What is Ionic Compound ?</h3>

An ionic compound is defined as the compound made up of ions that formed charge particles when an atom loses or gains electrons.

<h3>What is Cation ?</h3>

Cations are positively charged ions. It forms when an element lose one or more electrons.

The cation which has 18 electrons is Sn. Sn react with fluorine to form an ionic compound with the formula SnF₄ because Sn is large and F is very small in size.

Thus from the above conclusion we can say that Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

Learn more about the Ionic Compound here: brainly.com/question/2687188

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2 years ago