All categories

3 years ago

Totes need help on my question 3^-34x+5678-(-89÷32-2100035

2 answers:

8 0

3⁻³⁴ˣ + 5678 - (-89 / 32 - 2100035)
5.99 * 10⁻¹⁷ + 5678 + 89/32 + 2100035
5.99 * 10⁻¹⁷ + 5678 + 2.78 + 2100035
5.99 * 10⁻¹⁷ + 2105715.78

In short, Your Answer would be: 5.99 * 10⁻¹⁷ + 2105715.78

Hope this helps!

Allushta [10]3 years ago

5 0

‌1/16677181699666568‌x+‌67382905/32

You might be interested in

Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes through the point (-16, -11).

NISA [10]

Y = -4x - 2
P (-16, -11)
a = -4, b = 0, c = -2
m = -a/b
m = -(-4)/(-2)
m = 4/(-2)
m = -2

y-yo = m(x-xo)
y-(-11) = -2[x-(-16)]
y+11 = -2(x+16)
y+11 = -2x-32
2x+y+11+32 = 0
2x+y+43 = 0

A outra questão é semelhante.

4 0

2 years ago

Can someone help me in this algebra question please 100% correct

Artist 52 [7]

The answer is the 3rd choice. The beginning temperature is -9 so you add the 7 to the -9 degrees to find the temperature at noon because it increased.

7 0

3 years ago

25 times 55 wright it out please

lakkis [162]

Answer:

1375

Step-by-step explanation:

25*55= 1375

6 0

2 years ago

A concave octagon B convex quadrilateral C concave quadrilateral D convex octagon

balu736 [363]

Answer: concave

Step-by-step explanation:

4 0

3 years ago

Can anyone please explain? Need some help :)

DedPeter [7]

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = $\dfrac{\sqrt{3} }{4}s^2$

Side Length, s=6 Units

$\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units$

Area of the Hexagon

$= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)$

7 0

3 years ago