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Amiraneli [1.4K]
3 years ago
6

Totes need help on my question 3^-34x+5678-(-89÷32-2100035

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0
3⁻³⁴ˣ + 5678 - (-89 / 32 - 2100035)
5.99 * 10⁻¹⁷ + 5678 + 89/32 + 2100035
5.99 * 10⁻¹⁷ + 5678 + 2.78 + 2100035
5.99 * 10⁻¹⁷ + 2105715.78

In short, Your Answer would be: 5.99 * 10⁻¹⁷ + 2105715.78

Hope this helps!

Allushta [10]3 years ago
5 0
<span><span><span>‌<span>1/16677181699666568</span></span>‌x</span>+<span>‌<span>67382905/<span>32</span></span></span></span>
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A number y is five times greater than two added to a number x.write an expression for y in terms of x.if x = 3, what is y
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Answer:

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3 years ago
Can someone solve this
Natalka [10]

Option D:

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Solution:

Given data:

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Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.

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3 years ago
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Alik [6]

Answer:

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Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean \mu, standard deviation \sigma

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of Z = \frac{X - \mu}{\sigma}, in which \mu is the mean and \sigma is the standard deviation.

b. If the length of pregnancy is in the lowest a​%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of \frac{a}{100}, and X is given by: X = \mu - Z\sigma, in which \mu is the mean and \sigma is the standard deviation.

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Natalija [7]
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