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Phoenix [80]
4 years ago
5

A new electronics company, HOTWIRED, is working on two new docking stations to release this

Mathematics
1 answer:
inna [77]4 years ago
3 0

Answer:

The objective function is P(x,y) = 55x + 95y

P(600, 1400) is $166000

P(600, 1700) is $194500

P(1500, 1700) is $244000

P(1200, 800) is $142000

P(1500, 800) is $158500

They need to sell 1500 of the basic models  and 1700 of the advanced models to make the maximum profit

Step-by-step explanation:

Let us solve the question

∵ x denotes the number of  basic models

∵ y is the number of advanced models

∵ They will make $55 on each basic model

∵ They will make $95 on each advanced model

→ The profit is the total amount of money-making on them

∴ Profit = 55(x) + 95(y)

∴ Profit = 55x + 95y

∴ The objective function is P(x,y) = 55x + 95y

Let us test the vertices on the objective function

∵ The vertices are (600, 1400), (600, 1700), (1500, 1700), (1200, 800),

   and (1500, 800)

→ substitute each vertex in the objective function

∵ x = 600 and y = 1400

∴ P(600, 1400) = 55(600) + 95(1400) = 166000

∴ P(600, 1400) = $166000

∵ x = 600 and y = 1700

∴ P(600, 1700) = 55(600) + 95(1700) = 194500

∴ P(600, 1700) = $194500

∵ x = 1500 and y = 1700

∴ P(1500, 1700) = 55(1500) + 95(1700) = 244000

∴ P(1500, 1700) = $244000

∵ x = 1200 and y = 800

∴ P(1200, 800) = 55(1200) + 95(800) = 142000

∴ P(1200, 800) = $142000

∵ x = 1500 and y = 800

∴ P(1500, 800) = 55(1500) + 95(800) = 158500

∴ P(1500, 800) = $158500

∵ The greatest profit is $244000

→ That means the maximum profit will be with vertex (1500, 1700)

∴ They need to sell 1500 of the basic models  and 1700 of the

   advanced models to make the maximum profit

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