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amid [387]
3 years ago
12

I climb half the steps in a staircase. Next, I climb one-third of the remaining steps. Then I climb one-eight of the rest and st

op to catch my breath. What is the least possible number of steps in the staircase?
Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0

Given parameters:

   First sets of staircase  = \frac{1}{2}

   Next sets  = \frac{1}{3}

    Third sets  = \frac{1}{8}

Unknown:

The least possible number of steps =?

Solution:

The least possible number of steps will be the lowest common multiples of these sets of steps.

We want fractions that will give whole numbers because realistically, one cannot take half a step of a step.

 So, the number of steps must be a multiple of denominators of the fractions given.

   Denominators are 2 , 3 and 8

     Their least common multiple is 24;

    This the lowest number by which 2, 3 and 8 can all divide.

So, the least number is 24 steps

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640

Step-by-step explanation:

there is 1 gallon for every 128 ounces

so 1 gal= 128z

to find 5gal= ?oz

you multiply 128 by 5 which gives u 640

which gives u 640 oz

hope this helps

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Step-by-step explanation:

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3 years ago
Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartF
Vsevolod [243]

First of all, this problem is properly done with the Law of Cosines, which tells us

a^2 = b^2 + c^2 - 2 b c \cos A

giving us a quadratic equation for b we can solve.  But let's do it with the Law of Sines as asked.

\dfrac{\sin A}{a} = \dfrac{\sin B}{b} = \dfrac{\sin C}{c}

We have c,a,A so the Law of Sines gives us sin C

\sin C = \dfrac{c \sin A}{a} = \dfrac{5.4 \sin 20^\circ}{3.3} = 0.5597

There are two possible triangle angles with this sine, supplementary angles, one acute, one obtuse:

C_a = \arcsin(.5597)  = 34.033^\circ

C_o = 180^\circ - C_a = 145.967^\circ

Both of these make a valid triangle with A=20°.   They give respective B's:

B_a = 180^\circ - A - C_a = 125.967^\circ

B_o = 180^\circ - A - C_o = 14.033^\circ

So we get two possibilities for b:

b = \dfrac{a \sin B}{\sin A}

b_a = \dfrac{3.3 \sin 125.967^\circ}{\sin 20^\circ} = 7.8

b_o = \dfrac{3.3 \sin 14.033^\circ}{\sin 20^\circ} = 2.3

Answer: 2.3 units and 7.8 units

Let's check it with the Law of Cosines:

a^2 = b^2 + c^2 - 2 b c \cos A

0 = b^2 - (2 c \cos A)b + (c^2-a^2)

There's a shortcut for the quadratic formula when the middle term is 'even.'

b = c \cos A \pm \sqrt{c^2 \cos^2 A - (c^2-a^2)}

b = c \cos A \pm \sqrt{c^2( \cos^2 A - 1) + a^2}

b = 5.4 \cos 20 \pm \sqrt{5.4^2(\cos^2 20 -1) + 3.3^2}

b = 2.33958 \textrm{ or } 7.80910 \quad\checkmark

Looks good.

6 0
3 years ago
Read 2 more answers
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