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3 years ago

What is measure angle H

Mathematics

1 answer:

Setler [38]3 years ago

4 0

Because ∠HML and ∠GMI are vertical angles, that have the same angle:

3x-10.

Also, ∠HML and ∠MHL add up to 3x+6, you can set up the equation:

3x-10+y=3x+6

y-10=6

y=16.

Therefore, ∠H has an angle of 16°.

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6x + 4y=10 12x + y= -29

Olin [163]

Answer: x=-3 y=7.

Step-by-step explanation:

$\displaystyle\\\left \{ {{6x+4y=10\ \ \ \ \ (1)} \atop {12x+y=-29\ \ \ \ (2)}} \right.\\ We\ multiply\ both\ sides\ of\ equation\ (1)\ by\ -2:\\\left \{ {{(-2)*6x+(-2)*4y=(-2)*10} \atop {12x+y=-29}} \right. \\\\\left \{ {{-12x-8y=-20} \atop {12x+y=-29}} \right. \\$ $We\ summarize\ equations\ (1)\ and\ (2):\\-7y=-49\\-7*y=-7*7\\Divide\ both\ sides\ of\ the\ equation\ by\ -7:\\y=7.\\We\ substitute\ the\ value\ of\ y\ into \ equation\ (1):\\6x+4*7=10\\6x+28=10\\6x+28-28=10-28\\6x=-18\\6*x=6*(-3)\\Divide\ both\ sides\ of\ the\ equation\ by\ 6:\\x=-3.$

3 0

1 year ago

A box contains $7.05 in nickels, dimes, and quarters. There are 42 coins in all, and the sum of the numbers of nickels and dimes

german

I BELIEVE that there are 22 quarters, 13 dimes, and 7 nickels I’m super super sorry if wrong

3 0

3 years ago

How many extraneous solutions exist for the logarithmic equation below if it is solved in the most efficient way possible?log_(2

Nadusha1986 [10]

Answer:

No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

$\log_{2}[\log_{2}(\sqrt{4x})]=1$

i.e. $\log_{2}(\sqrt{4x})=2^{1}$

i.e. $\sqrt{4x}=2^{2}$

i.e. $\sqrt{4x}=4$

i.e. $4x=4^{2}$

i.e. $4x=16$

i.e. $x=4$

So, the solution of the given equation is x=4.

Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is $( 0,\infty )$ .

Therefore, the domain of the given function is x > 0.

We know that the extraneous solution is the solution which does not belong to the domain.

But as x=4 belongs to the domain x > 0.

Thus, x = 4 is not an extraneous solution.

Hence, this equation does not have any extraneous solution.

7 0

3 years ago

Read 2 more answers

I really need help a and b

Ivan

Using BEDMAS

a) 6+4(2+3)^2
6+4(5)^2 - Eliminate addition in bracket
6+4(25) - Execute the exponent
6+100 - Mulitplying
106 - Addition

b)(6+4)(2+3)
(10)(5) -Addition in BRACKETS done
50 - Mulipication

If you found that helpful please rate as "Brainiest" if not comment below :)

5 0

3 years ago

Read 2 more answers

Solve for w: v = 3p (w -r)

notka56 [123]

Answer:

Step-by-step explanation:

v=3p(w-r)

v=3pw-3pr

v+3pr=3pw

(v+3pr)/3p=w

7 0

3 years ago