Answer:
![E' = \frac{1}{8} E](https://tex.z-dn.net/?f=E%27%20%3D%20%5Cfrac%7B1%7D%7B8%7D%20E)
Explanation:
Given data:
first case
Distance of electric field from center of sphere is r_1 <R
Electric field at r_1< R
![E = \frac{kQr_1}{R^3}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BkQr_1%7D%7BR%5E3%7D)
second case
Distance of electric field from centre of sphere is r_1 < 2R
Electric field at r_1< 2R
![E' = \frac{kQr_1}{8R^3}](https://tex.z-dn.net/?f=E%27%20%3D%20%5Cfrac%7BkQr_1%7D%7B8R%5E3%7D)
so, we have
![E' = \frac{1}{8} E](https://tex.z-dn.net/?f=E%27%20%3D%20%5Cfrac%7B1%7D%7B8%7D%20E)
Answer:
Explanation:
The increase of women in the paid workforce was arguably the most significant change in the economy in the past century. In the U.S., women's participation in the labor market has nearly doubled, from 34% of working-age women (age 16 and older) in the labor force in 1950 to almost 57% in 2016.
Answer:
K
Explanation:
Given that
Elements Density
K 0.86 g/cm³
Ca 1.5 g/cm³
Sc 3.2 g/cm³
Ti 4.5 g/cm³
As we know that density of the BCC ( body centered cubic )element is lower than the FCC(Face centered cubic )element.
In the given problem only K have lower density all of these element that is why is in BCC and all others are in FCC.
The packing efficiency of the FCC structure element is higher than the BCC element that is why FCC is more denser than BCC.And also FCC having good packing of element.
Answer:
![I = \frac{mvb}{6}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7Bmvb%7D%7B6%7D)
Explanation:
we know angular velocity in terms of moment of inertia and angular speed
ω .... (1)
moment of inertia of rod rotating about its center of length b
........ .(2)
using v = ωr
where w is angular velocity
and r is radius of rod which is equal to b
so we get 2v = ωb
ω = 2v/b ................. (3)
here velocity is two time because two opposite ends are moving opposite with a velocity v so net velocity will be 2v
put second and third equation in ist equation
×
so final answer will be ![L = \frac{mvb}{6}](https://tex.z-dn.net/?f=L%20%20%3D%20%20%20%5Cfrac%7Bmvb%7D%7B6%7D)