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Archy [21]
3 years ago
15

If you stood on Mars and lifted a 15kg pack,you would be pulling with a force greater than...

Physics
1 answer:
Oxana [17]3 years ago
6 0

Answer: See answers below.

Explanation: In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

Mercury

Venus

Moon

Mars

Jupiter

Saturn

Uranus

Neptune

Pluto

In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

Mercury

Venus

Moon

Mars

Jupiter

Saturn

Uranus

Neptune

Pluto

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how many days does it take a team of drivers to drive a truck california and back to lansing if the drivers average 15m/s includ
Scilla [17]

Answer:

t = 2.2 [days] and is there is a round trip, it will be double time t = 4.4 [days]

Explanation:

First, we need to arrange the problem to work in the same unit system (SI).

We need to convert the 1800 [miles] to meters, therefore:

1800[miles] * \frac{1609.34[m]}{1[mile]} }=2896812[m] = 2896.8[km]

Now using the following equation of kinematics, for the avarage velocity  we have:

v=\frac{x}{t} \\where \\v=velocity [m/s]\\t = time [s]\\x=distance traveled [m]\\

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t=\frac{x}{v} \\t=\frac{2896812}{15}\\ t=193120.8[s]

Now we can convert from seconds into days.

193120.8[s]*\frac{1[hr]}{3600[s]}*\frac{1[day]}{24[hr]}\\  t = 2.2[days]

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t= 4.4 [days]

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