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Lesechka [4]
3 years ago
8

A lift moves up and down with an acceleration of 3 metre per second square .in each case calculate the relation of the floor on

each man of mass 50 kg standing on a lift.​
Physics
1 answer:
AysviL [449]3 years ago
5 0

Answer:

150\ N

Explanation:

We\ are\ given:\\Acceleration\ of\ the\ elevator= 3\ m/s^2\\Assumed\ mass\ of\ the\ man\ standing\ on\ it=50\ kg\\We\ know\ that,\\Force=Mass*Acceleration\\Or,\\F=ma\\Hence,\\Substituting\ m=50, a=3\ m/s^2,\\Force\ acting\ on\ the\ floor\ of\ the\ elevator=3*50=150\ Newtons

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a person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of 18 m/s. The cliff is 52 m above the
Alexxx [7]
You already have the speed, now you need the time.
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S=Speed    D=Distance   T=Time.
So here we have, 18m/s = 52m/T
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.3461 seconds is how long it took the stone to reach the water.
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4 years ago
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What is the speed of a jet plane that flies 8100 km in 27 hours (in km/hr)
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3 years ago
You build a grandfather clock, whose timing is based on a pendulum. You measure its period to be 2s on Earth. You then travel wi
Elenna [48]

Answer:

\frac{g_{2}}{g_{1}} = \frac{1}{4}

Explanation:

The period of the simple pendulum is:

T = 2\pi\cdot \sqrt{\frac{l}{g} }

Where:

l - Cord length, in m.

g - Gravity constant, in \frac{m}{s^{2}}.

Given that the same pendulum is test on each planet, the following relation is formed:

T_{1}^{2}\cdot g_{1} = T_{2}^{2}\cdot g_{2}

The ratio of the gravitational constant on planet CornTeen to the gravitational constant on planet Earth is:

\frac{g_{2}}{g_{1}} = \left(\frac{T_{1}}{T_{2}} \right)^{2}

\frac{g_{2}}{g_{1}} = \left(\frac{2\,s}{4\,s} \right)^{2}

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5 0
4 years ago
The cost of buying shirts is partly constant and partly varies with the number of shirts bought. When the number of shirts is 5
Jet001 [13]

Answer:

The cost of the buying the shirts is #9680

Explanation:

let the cost of buying shirt = C

let the number of shirt bought = N

The following equation can be generated based on the statement above;

C = k + Nb

When the cost, C = #240, the number of shirt = 5

240 = k + 5b ------ equation (1)

where;

k and b are constants

When the cost, C = #400, the number of shirt = 10

400 = k + 10b ------ equation (2)

From equation (1), make k the subject of the formula;

k = 240 - 5b ---- equation (3)

Substitute in the value of k into equation (2)

400 = k + 10b

400 = (240 - 5b) + 10b

400 = 240 - 5b + 10b

400 - 240 = -5b + 10b

160 = 5b

b = 160 / 5

b = 32

From equation (3), calculate k

k = 240 - 5b

k = 240 -5(32)

k = 240 - 160

k = 80

When the number of shirts bought = 300, the cost of the buying the shirts =

C =  k + Nb

C = 80 +32N

Where;

N is the number of shirts

C = 80 + 32(300)

C = 80 + 9600

C = #9680

Therefore, the cost of the buying the shirts is #9680

8 0
3 years ago
which type of landform develops at plate boundaries were one oceanic plate desends beneth another oceanic plate
viktelen [127]
Umm I think the ocean floor but I don't think so
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