Add 1/8 + 3/8 A. 3/64 B. 4/64 C. 4/16 D. 4/8

Mathematics

1 answer:

Alborosie2 years ago

3 0

Answer:

D. 4/8

Step-by-step explanation:

First you should have the same denominator. In this case you have it so you continue. And now you have to add the numerators together. So you get 4/8. You can also simplify it and divide the numerator and denominator by 4 and get 1/2

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Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being

Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new equipment, and this sample has a standard deviation of 0.047.

Let $\sigma$ = standard deviation of weights of new equipment.

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.065 {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, $H_A$ : $\sigma$ < 0.065 {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here One-sample chi-square test statistics;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 0.047

n = sample of quarters = 25

So, the test statistics = $\frac{(25-1)\times 0.047^{2} }{0.065^{2} }$ ~ $\chi^{2}__2_4$

= 12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0

3 years ago

The data show the number of viewers for television stars with certain salaries. Find the regression equation, letting salary be

larisa86 [58]

Answer:

y = 5.064 - 0.010x

Here, in this question x = 33

y = 4.734 million views

In this question data is missing and I filled it out and calculated the questions accordingly. Please refer to the attachment for the data calculated.

Step-by-step explanation:

First of all, this question is incomplete. It lacks the data needed to calculate the required things.

So, I figured out the question and I will try my best to solve the question at hand.

I have calculated the some data sheet in excel. Please refer to the attachment for that data.

let a be the salaries

b be the viewers

$S_{aa}$ = ∑ $a^{2}$ - $\frac{ Summtion a^{2} }{n}$