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Kaylis [27]
2 years ago
14

Which number is equivalent to 2.108¯¯¯¯¯¯¯¯?

Mathematics
1 answer:
antoniya [11.8K]2 years ago
4 0

Answer:

4.443664/2

Step-by-step explanation:

Mark me brainliest

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✨Plz help me well mark brainliest if u have a explanation!✨
Svetradugi [14.3K]
Did they give you the tax rate, or are you supposed to include the tax in the price of one bottle?
6 0
3 years ago
Justin cuts a 10-inch-long roll of cookie dough into 6 equal-length pieces. How many inches long is each piece of cookie dough?
mixas84 [53]

Answer: Each piece is 1 2/3 inch length.

Step-by-step explanation:

Total length of cookie dough =10-inch

Since it is being into divided  into 6 equal-length pieces

We have that each piece will have=1 0-inch / 6 = 5/3 = 1 2/3 inch length.

6 0
3 years ago
It takes 28 minutes for 7 people to paint 7 walls. How many minutes does it take for 14 people to paint 14 walls?
Paraphin [41]

Answer:

Since it takes 7 people 28 minutes to paint 7 walls, it must take 1 person 28 minutes to paint each wall. Therefore, 14 people must also take 28 minutes to paint 14 walls, as each person still paints 1 wall individually.

4 0
4 years ago
Read 2 more answers
Suppose there is a 21.9% probability that a randomly selected person aged 20 years or older is a jogger. In addition, there is a
Stells [14]

Answer:

The value P(F\ n \  J) = 0.05

The answer is No

Step-by-step explanation:

From the question we are told that

The probability a person is a jogger is P(J) =  21.9 \% =  0.219

The probability that a person is female given that she jogs is P(F|J)  =  21.9 \%  = 0.219

Generally the probability that a randomly selected person aged 20 years or older is female and jogs? Would it be unusual to randomly select a person aged 20 years or older who is female and jogs is mathematically represented as

P(F\ n \  J) = P(J)* P(F|J)

=>    P(F\ n \  J) = 0.219* 0.219

=>    P(F\ n \  J) = 0.05

Given that the probability is  equal to 0.05 then it is not unusual

8 0
3 years ago
A train station has installed a system for determining whether bags contain explosives. It has a 95% chance of correctly identif
astraxan [27]

Answer:

a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)

=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363

hence  probability that it actually contains explosives given identified as containing explosives)

=(10/(4*106))*0.95/0.005002363=0.000475

b)

let probability of correctly identifying a bag without explosives be a

hence a =0.99999763 ~ 99.999763%

c)

No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,

3 0
4 years ago
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