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kvasek [131]
3 years ago
7

Compare 9 × (11 – 4) and 3 × (11 – 4). A. 9 × (11 – 4) is three times as much as 3 × (11 – 4). B. 9 × (11 – 4) is nine times as

much as 3 × (11 – 4). C. 3 × (11 – 4) is three times as much as 9 × (11 – 4). D. 9 × (11 – 4) is six times as much as 3 × (11 – 4).
Mathematics
2 answers:
liubo4ka [24]3 years ago
3 0

Hello there!

So there are two separate problems: 9 * (11-4) and 3 * (11-4). To find the value for each expression, use order of operations. We'll solve what's in the parenthesis before multiplying that value by the other number. 11-4 is 7. 7 * 9 is 63. 11-4 is 7. 7 * 3 is 21. You can divide 63 by 21 to get 3. This means that 9 * (11 - 4) is three times as much as 3 *(11 - 4). Even just by looking at the problem, the expression in the parenthesis is the same thing, but the front numbers are different. 9 is three times as much as 3.  The answer is A.

Stolb23 [73]3 years ago
3 0

Answer:

a

Step-by-step explanation:

So there are two separate problems: 9 * (11-4) and 3 * (11-4). To find the value for each expression, use order of operations. We'll solve what's in the parenthesis before multiplying that value by the other number. 11-4 is 7. 7 * 9 is 63. 11-4 is 7. 7 * 3 is 21. You can divide 63 by 21 to get 3. This means that 9 * (11 - 4) is three times as much as 3 *(11 - 4). Even just by looking at the problem, the expression in the parenthesis is the same thing, but the front numbers are different. 9 is three times as much as 3.  The answer is A.

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To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(x^2 + 4)(x^2 - 4)

x^2 * x^2

x^4

Outside:

(x^2 + 4)(x^2 - 4)

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(x^2 + 4)(x^2 - 4)

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Last:

(x^2 + 4)(x^2 - 4)

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Now combine all the products of the FOIL together like so...

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Combine like terms:

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