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4 years ago

The legs of a right triangle are 10 cm and 24 cm. What is the length of the hypotenuse?

Mathematics

2 answers:

Anastaziya [24]4 years ago

7 0

Answer:

The length of the hypotenuse is 26 cm.

Step-by-step explanation:

It is given that the legs of a right triangle are 10 cm and 24 cm.

we need to find the length of the hypotenuse.

According to the Pythagoras theorem,

$hypotenuse^2=leg_1^2+leg_2^2$

Substitute $leg_1=10$ and $leg_2=24$ in the above formula.

$hypotenuse^2=(10)^2+(24)^2$

$hypotenuse^2=100+576$

$hypotenuse^2=676$

Taking square root on both sides.

$\sqrt{hypotenuse^2}=\sqrt{676}$

$hypotenuse=26$

Therefore the length of the hypotenuse is 26 cm.

n200080 [17]4 years ago

6 0

To determine the length of the hypotenuse, apply Pythagorean theorem.

A^2 + B^2 = C^2
(10)^2 + (24)^2 = C^2
100 + 576 = C^2
676 = C^2
C = 26 cm.

The hypotenuse is 26 cm.

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tino4ka555 [31]

Answer:

$\large \boxed{\sf \ \ \ 3\cdot a \cdot b \ \ \ }$

Step-by-step explanation:

Hello,

First of all, let's find the factors of these two numbers and I will put <u>in boxes the common factors.</u>

$15a^2b^2=\boxed{3}\cdot 5\cdot \boxed{a} \cdot a \cdot \boxed{b} \cdot b \\ \\ \\-24ab=(-1)\cdot 2 \cdot \boxed{3} \cdot 4 \cdot \boxed{a} \cdot \boxed{b}$

The Highest Common Factor (HCF) is found by finding all common factors and selecting the largest one. So, in this case, it gives

$\large \boxed{\sf \ \ \ 3\cdot a \cdot b \ \ \ }$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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4 years ago

The booster club sells meals at basketball games. Each meal comes with a choice of hamburgers, pizza, hot dogs , cheeseburgers o

LenKa [72]

Answer:

6*5=30

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4 years ago

Read 2 more answers

ABDE is a rectangle on coordinate axes, the sides of the rectangle are parallel to the axes,

Hitman42 [59]

The coordinates of B and D are the location of the vertices B and D in the rectangle

The coordinates of B and D are (55, 30) and (55, 14)

<h3>How to determine the coordinates of B and D?</h3>

From the figure of the rectangle, we have:

A = (25,30)

C = (40, 22)

Point B has the same y-coordinate as point A

So, we have:

B = (x, 30)

The x-coordinate is then calculated as:

Bx = 2Cx - Ax

This gives

Bx = 2*40 - 25

Bx = 55

So, the coordinates of B are:

B = (55, 30)

Point D has the same x-coordinate as point B

So, we have:

D = (55, y)

The y-coordinate is then calculated as:

Dy = Cy - (By - Cy)

This gives

Dy = 22 - (30 - 22)

Dy = 14

So, the coordinates of B are:

D = (55, 14)

Hence, the coordinates of B and D are (55, 30) and (55, 14)