Question

Subtract 2+ 3a2 -12ab +4b2 from 1+ 8a2+16ab +2b2​

Answer 1

Answer:11a²+8ab+1+2b²

Step-by-step explanation:

Answer 2

The answer of the following subtraction is 5$a^{2} -2b^{2} +28ab$

Step-by-step explanation:

As per the question the equation will be

$(1+8a^{2}+16ab+2b^{2} ) - (2+3a^{2} -12ab+4b^{2} )$

To find the subtraction,

The steps are as follow

=$1+8a^{2} +16ab+2b^{2} - 2 -3a^{2} +12ab-4b^{2}$

=1-2 + $8a^{2} -3a^{2} +2b^{2} -4b^{2} +16ab+12ab$

[ we took the variables with same power together]

=5$a^{2} -2b^{2} +28ab$

Hope it helps you.