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2 years ago

HELP ASAP WILL GIVE BRAINLY

Mathematics

1 answer:

Mila [183]2 years ago

8 0

Answer:

1 and 2 are not polyhedrons, as a circle has infinite sides

1. cone, 1 vertex

2. sphere, nothing

3. pentagonal prism?

wait but can't every face be a base???

anyway 7 faces, 10 vertices

4. triangular prism

5 faces, 6 vertices

Step-by-step explanation:

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I need to find the area of the triangle TYY

Rufina [12.5K]

Answer:

20cm Squared

Step-by-step explanation:

Area of a Triangle = Base X Hight divided by 2

= 5 X 8 Divided by 2

= 40 Divided by 2

= 20cm Squared

8 0

2 years ago

6 friends share 15 oz bag of nuts equally between what two whole numbers of ounces will each person get

Nady [450]

They only way i see possible for 6 friends to share evenly is if each get 2.50 oz each

5 0

2 years ago

Read 2 more answers

IN A RECTANGLE ABCD, BD=34 AND OC=3X+5 WHAT IS THE VALUE OF X

stiv31 [10]

Answer:

The rectangle has sides AB, BC, CD, and AD. Then AC and BD are diagonals of the rectangle. The diagonals have the same length.

AC = BD

3x + 15 = 4x - 5

Solve the equation for x.

x = 20

Plug this value of x back into any of the expressions.

Step-by-step explanation:

4 0

2 years ago

Use a power series to approximate the value of the integral with an error of less than 0.0001. (Round your answer to four decima

otez555 [7]

Answer:

The answer is "0.9461"

Step-by-step explanation:

Given:

$\int^1_0 \frac{sin(x)}{x} dx\\\\$

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $\sum^2_{n=0}\frac{(-1)^n x^{2n+1} (-1)^n (x-1)^n}{(2n + 1)!}$

$\therefore$

$\to \sin x = \sum^{\infty}_{n=0} (-1)^n\frac{x^{(2n+1)}}{(2n + 1)!}$

$\because \\\\ \to \frac{\sin x}{x} =\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1-1}}{(2n+1)!}\\$

$=\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n}}{(2n+1)!}$

The value is in between 0 and 1 then:

$\to \int^1_0 \frac{sin(x)}{x} = =\sum^{2}_{n=0} \frac{(-1)^n}{ (2n+1) (2n+1)!}$

The above-given series is an alternative series, and it will give an error, when the nth term is bounded by its absolute value, that can be described as follows:

$\to \frac{1}{(2n+3) (2n+3)!}< 0.0001\\\\\to (2n+3) (2n+3)!> 0.0001\\\\\to n\geq 2 \\$

So,

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $1 - \frac{1}{3 \cdot 3!}+\frac{1}{5 \cdot 5!}\\\\$

$\approx 1 - \frac{1}{3 \cdot 6}+\frac{1}{5 \cdot 120}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx \frac{18-1}{18}+\frac{1}{600}\\\\\approx \frac{17}{18}+\frac{1}{600}\\\\\approx \frac{1700+3}{1800}\\\\ \approx \frac{1703}{1800}\\\\\approx 0.9461$

5 0

2 years ago

Change 5/8 to a percentage. <br> A. 87.5%<br> B. 62.5%<br> C. 92.5%<br> D. 37.5%

lawyer [7]

5/8 = 5 ÷ 8 = .625

move decimal 2 places to right for %

.625 = 62.5%

6 0

2 years ago