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Ira Lisetskai [31]
3 years ago
12

HELP ASAP WILL GIVE BRAINLY

Mathematics
1 answer:
Mila [183]3 years ago
8 0

Answer:

1 and 2 are not polyhedrons, as a circle has infinite sides

1. cone, 1 vertex

2. sphere, nothing

3. pentagonal prism?

wait but can't every face be a base???

anyway 7 faces, 10 vertices

4. triangular prism

5 faces, 6 vertices

Step-by-step explanation:

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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
Mr.Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, how much is his overall budget?
oee [108]

\frac{800}{x}  = \frac{16\%}{100\%}  \\  \frac{80000}{16}  =  \frac{16x}{16}  \\ 5000 = x
5 0
3 years ago
Which two integers is √65 between?
goblinko [34]
The answer to this math problem is the multiple is 1 5 13
7 0
3 years ago
Read 2 more answers
A local store is offering 20% off regular priceiPods. The original price is $200, how much willthe iPod cost during the sale?
Tju [1.3M]
This is the answer :
100%-20%=80%
\frac{80}{100}  =  \frac{x}{200}  \\ x =  \frac{200 \times 80}{100}  =  \frac{16000}{100}  = 160
the answer $160
8 0
3 years ago
Helppppp!!!!!! Plsss
PtichkaEL [24]

Answer:

A!

Step-by-step explanation:

open circle = the number it's on isn't an answer

the arrow is pointing left, the negative side so it's less than :)

6 0
3 years ago
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