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3 years ago

Can someone help me please

Mathematics

2 answers:

Kaylis [27]3 years ago

8 0

The answer is H, 2 5/6

lisabon 2012 [21]3 years ago

8 0

The answer is 2 5/6 so that means it is the letter H

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The level of nitrogen oxides (NOX) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies No

Greeley [361]

Answer:

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.02 g/mi

Standard Deviation, σ = 0.01 g/mi

Sample size, n = 81

We are given that the distribution of level of nitrogen oxides is a bell shaped distribution that is a normal distribution.

Standard error due to sampling:

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.01}{\sqrt{81}} = 0.0011$

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.01

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 0.02}{0.0011})=0.01$

$= 1 -P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.01$

$=P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.99$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 0.02}{0.0011} = -2.326\\\\x = 0.0174$

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.

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A process is normally distributed and in control, with known mean and variance, and the usual three-sigma limits are used on the

Aleks [24]

Answer:

Check the explanation

Step-by-step explanation:

Ans=

A: For m = 5: P(³≥1) = 1 – P(³=0) = 1 – 0.9973^5 = 0.0134

M = 10: 1 – 0.9973^10 = 0.0267

M = 20: 1 – 0.9973^20 = 0.0526

M = 30: 1 – 0.9973^30 = 0.0779

M = 50: 1 – 0.9973^50 = 0.126

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Ans=

Going by the question and the explanation above, we derived sample values of the mean as well as standard deviation in calculating our probability, since that is the necessary value in determining the probability of an out-of-bounds point being plotted. Furthermore, we would know that that value for the possibility would likely be a poor es²ma²on, cas²ng doubt on anycalcula²ons we made using those values

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