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3 years ago

Nitrogen gas effuses through an opening 1.59 times faster than an unknown gas.

1 answer:

5 0

A) Nitrogen has an ATOMIC mass number of 14, but nitrogen gas consists of N₂ molecules, so the mass to use in this problem is 28 g/mol. Rates of effusion ∝ 1/√(mass), so

√(mass unknown) /√28 = (rate N₂ effusion)/(rate unknown effusion) = 1.59 
∴ mass unknown = (1.59)²(28) = 70.78 g/mol 

B) One possible gas that comes close for this mass is NF₃.

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Juliette [100K]

Answer:

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Explanation:

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6 0

3 years ago

Convert 533 cm/s to units of meters per minute. Show the unit analysis by dragging the conversion factors into the unit‑factor s

lukranit [14]

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

8 0

3 years ago

g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the

Sliva [168]

Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass = Volume × Density

Thus; the mass of the water = 250 mL × 1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature $T_1$ = 20.0° C

the final temperature $T_2$ = 99° C

Change in temperature $\Delta T$ = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms $\Delta T$

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = $6.626 \times 10^{-34} \ J.s$

c = velocity of light = $3.0 \times 10^8 \ m/s$

= $\dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}$

= $1.59024 \times 10^{-24}$ J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = $\dfrac{82555 J}{1.59024 \times 10^{-24}J}$

The total photons required = 5.19 × 10²⁸ photons

5 0

3 years ago

What is the majority of 0.50 g of na dissolved in a 1.5 L solution

Oxana [17]

The correct answer is 0.014467 M.

Molarity is defined as the number of moles present in a liter solution, that is, number of moles / liter solution.

The molar mass of sodium (Na) is 23.0 g/mol

Thus, 1 mole of Na contains 23.0 g

Now, x moles of Na contains 0.50 g

Moles = 0.50 × 1 / 23.0

Moles = 0.50 / 23.0

= 0.0217 moles of Na

Molarity = Number of moles / liters of solution

= 0.0217 / 1.5

= 0.014467 M

8 0

3 years ago

Iodine-131 decays with a half-life of 8.02

dlinn [17]

Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = $\frac{2.303}{t} X log \frac{initial.conc}{final.conc}$

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = $\frac{2.303}{6.01} X log \frac{5}{final.conc}$
∴ final conc. = 2.975 mg

3 0

3 years ago