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12345 [234]
3 years ago
11

What is the 1/2 half life of Cesium 137 in years?

Chemistry
2 answers:
blondinia [14]3 years ago
8 0

Answer:

About 30.17 years

Explanation:

About 94.6% decays by beta emission to a metastable nuclear isomer of barium: barium-137m . The remainder directly populates the ground state of barium-137, which is stable.

svetoff [14.1K]3 years ago
4 0

Answer:

about 30.17 years

Explanation:

Caesium-137 has a half-life of about 30.17 years. About 94.6% decays by beta emission to a metastable nuclear isomer of barium: barium-137m (137mBa, Ba-137m). The remainder directly populates the ground state of barium-137, which is stable.

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What is the temperature of 0.47 mol of gas at a pressure of 1.5 atm and a volume of 10.5 l ?
Whitepunk [10]
The temp is 0.002448 of the equation
5 0
3 years ago
If enough changes occur in the gene pool of a species, it is possible that a new species would be created.
lianna [129]

Answer:

Yes

Explanation:

A gene pool is the sum total of all the genes(sum of alleles)of a species and population at any given time is known as gene pool.

The new species are created in nature by four mechanisms such as geographic isolation (allopatric speciation), reproductive isolation (sympatric speciation), mating behaviour (parapatric speciation).

Due to any of these factors when population acquire unique changes in their genes and enough changes have been introduced in the gene pool of the population with time, two population become distinct from each other and not able to interbreed leads to the formation of new species.

6 0
3 years ago
D-Fructose is the sweetest monosaccharide. How does the Fischer projection of D-fructose differ from that of D-glucose? Match th
Aleks04 [339]

Answer:

aldehyde

carbon-1

ketone

carbon-2

Explanation:

Monosaccharides are colorless crystalline solids that are very soluble in water. Moat have a swwet taste. D-Fructose is the sweetest monosaccharide.

In the open chain form, monosaaccharides have a carbonuyl group in one of their chains. If the carbonyl group is in the form of an aldehyde group, the monosaccharide is an aldose; if the carbonyl group is in the form of a ketone group, the monosaccharide is known as a ketose. glucose is an aldose while fructose is a ketose.

In D-glucose, there is an aldehyde functional group, and the carbonyl group is at carbon-1 when looking at the Fischer projection.

In D-fructose, there is a ketone functional group, and the carbonyl group is at carbon-2 when looking at the Fischer projection.

6 0
3 years ago
g Select the correct statements. I. Reduction is the loss of electrons, and oxidation is the gain of electrons II. Reduction is
Karolina [17]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Reduction reaction is defined as the reaction in which a substance gains electrons. Here, the oxidation state of the substance decreases.

X^{n+}+ne^-\rightarrow X

Oxidizing agents are the agents that helps in the oxidation of other substance and itself gets reduced. These agents undergoes reduction reactions.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. Here, oxidation state of the substance increases.

X\rightarrow X^{n+}+ne^-

Reducing agents are the agents that helps in the reduction of the other substance and itself gets oxidized. These agents undergoes reduction reactions.

Oxidation state is the number which is given to an atom when it looses or gains electron. It is written as a superscript. In a compound, the total charge is equal to the sum of the charges of all atoms in that compound. <u>For Example:</u> In MnO_4^-, manganese has +7 oxidation number and oxygen has -2.

So, the charge on the compound = [=7+(4\times (-2))]=-1

Hence, the correct answer is Option D.

6 0
3 years ago
An organism that makes or creates their own food?
Sedaia [141]

I think producer

option is A

5 0
3 years ago
Read 2 more answers
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