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3 years ago

What is the 1/2 half life of Cesium 137 in years?

Chemistry

2 answers:

blondinia [14]3 years ago

8 0

Answer:

About 30.17 years

Explanation:

About 94.6% decays by beta emission to a metastable nuclear isomer of barium: barium-137m . The remainder directly populates the ground state of barium-137, which is stable.

svetoff [14.1K]3 years ago

4 0

Answer:

about 30.17 years

Explanation:

Caesium-137 has a half-life of about 30.17 years. About 94.6% decays by beta emission to a metastable nuclear isomer of barium: barium-137m (137mBa, Ba-137m). The remainder directly populates the ground state of barium-137, which is stable.

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What volume (in mL ) of 0.200 M NaOH do we need to titrate 40.00 mL of 0.140 M HBr to the equivalence point?

Ugo [173]

NaOH + HBr =⇒ NaBr + H2O

35.0 ml HBr x 1 liter/1000 mL x 0.140 moles HBr/ liter = 0.0049 moles HBr

0.0049 moles HBr x 1mole NaOH/1mole HBr = 0.0049 moles HBr

0.0049 moles HBr x 1 liter NaOH/0.200 moles NaOH x 1000 mL/1liter= 24.5 mL NaOH

7 0

3 years ago

Read 2 more answers

Calculate the volume of .5 molecsample of gas at 140 k and a pressure of 1.2 atm

nlexa [21]

582 ml is the volume of gas.

Answer:

Explanation:

Using the ideal law of gases, the kinetic theory of gas can be stated as

PV = nRT

Here P is the pressure and it is given as 1.2 atm, V is the volume, which we need to find. Then R is the gas constant and T is the temperature while n is the concentration present.

As per the give question, P = 1.2 atm, T = 140 K and n = 0.5 moles, R = 8.314

V = $\frac{nRT}{P}$

V = $\frac{(0.5*8.314*140}{1.2}= 582 l.$

So 582 ml is the volume of gas.

6 0

3 years ago

If your good at science please help

Nataly [62]

This is biology btw :P arteries carry oxygenized blood away from heart, veins carry deoxygenized blood back to heart, and capillaries are tiny networks of blood vessels that give blood(oxygen) to body tissues

3 0

4 years ago

Why blowing at the ping ping ball did not change its shape and size?

goldfiish [28.3K]

Answer:

Because it does not have to

Explanation:

Why because when you blow at it it might move it does not change it's shape because it is a solid

4 0

2 years ago

How many moles and numbers of ions of each type are present in the following aqueous solution? 63.1 mL of 1.85 M magnesium chlor

Alexxandr [17]

Answer:

We have 0.117 moles Mg^2+ and 0.234 moles Cl-

The number of Mg^2+ ions = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

Explanation:

Step 1: Data given

Volume of magnesium chloride = 63.1 mL

Concentration of solution = 1.85 M

Step 2: Calculate moles MgCl2

Moles MgCl2 = concentration * volume

Moles MgCl2 = 1.85 M * 0.0631 L

Moles MgCl2 = 0.117 moles

Step 3: Calculate moles of ions

MgCl2 → Mg^2+ + 2Cl-

For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-

For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-

The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

4 0

4 years ago