3 years ago

Is this right, I feel like its wrong

Chemistry

1 answer:

hjlf3 years ago

7 0

It is correct, next time re-check your answer and don't second guess yourself. ;3

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What fraction of 2 years is 10 months <br>

zzz [600]

Answer:

10/24

Simplified: 5/12

Explanation:

Well first, let's convert years into months

1 year = 12 months which means 2 years = 24 months

In fraction form we would write this as 10/24

If the question asks for it to be simplified, then simply

Both 10 and 24 evenly fit 2

Therefore, divide both the numerator and the denominator by 2

10 ÷ 2 / 24 ÷ 2

5/12

This can no longer be simplified

8 0

3 years ago

Which of the following bonds is the strongest?

mr Goodwill [35]

The answer to this question will be c

3 0

3 years ago

If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).

11111nata11111 [884]

Answer:

${ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 = \frac{11}{m _{r}} \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\ \\ { \bf{vapour \: density = 2 \times m _{r}}} \\ = 2 \times 14.85 \\ = 29.7 \: { \tt{g {dm}^{ - 3} }}$

7 0

3 years ago

in a typical person, the level of glucose is about 85 mg/ 100 mL of blood. if an average body contains about 11 pt of blood, how

Vanyuwa [196]

Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.

We make a proportion out of the word problem

(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose

5 0

3 years ago

Balance the following equation. Then, given the moles of reactant or product below, determine the corresponding amount in moles

Mrrafil [7]

Answer:

Option a → 4 mol NH₃

Explanation:

This the unbalanced reaction

NH₃ + O₂ ⟶ N₂ + H₂O

The balanced reaction:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

4 mol of ammonia

3 mol of oxygen

2 mol of nitrogen

6 mol of water

6 0

3 years ago