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Ksenya-84 [330]
3 years ago
5

Victor pours 100 grams of oil into a beaker filled with 1,000 grams of water. What is the total mass of his mixture? A. 100,000

grams B. 1,100 grams C. 900 grams D. 10 grams
Chemistry
2 answers:
Anna71 [15]3 years ago
7 0

The answer is 1,100 Grams.

tino4ka555 [31]3 years ago
6 0
The total mass of his mixture is 100,000 grams. (Answer A)
You multiply 1,000 grams of water by 100 to get 100,000 grams.
So the total mass of Victor's mixture is 100,000 grams
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8 0
3 years ago
100 points
nordsb [41]

Hello!

My argument: Which is better a Ps4 or an Xbox 1


The Ps4 is a better all-round console. The PS4 costs $100 less but has less games than the Xbox 1. The Xbox 1 now came up with dual compatible games. This means that certain games can now run on the Xbox 1 and the Xbox 360. The overall winner is really undetermined. The controller for Xbox has more quicker response time and is specifically built to be an extremely comfortable in your hands. Unlike the PS4 which their controller is built for nothing they really didn't do anything to theirs. Although the console comparisons are the same. The hard drive for the Xbox is non- removable meaning that if you want the hard drive. you would have to break the Xbox to get it . Unlike the Ps4 when you can take it out easily and switch it with any console and still have your data. I am an Xbox fan since for ever but I think that the two consoles are built the same.


Hope it helps!



7 0
3 years ago
Read 2 more answers
Why was mass lost from the crucible during the reaction?
Alexxandr [17]
If the crucible wasn't covered with a lid the reactants may have produced a gas that was released into the surroundings, or mass may have been lost in the form of water vapour.
6 0
3 years ago
What is the total probability of finding a particle in a one-dimensional box in level n = 4 between x = 0 and x = L/8?
Lubov Fominskaja [6]

Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})

Hence, the probability of finding the particle in the  one-dimensional box is:

P = \int_{x_{1}}^{x_{2}} \psi^{2} dx

P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx

P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]

P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})    

Solving for n=4:

P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})    

P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})    

P = \frac{1}{8}

I hope it helps you!

7 0
3 years ago
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