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sattari [20]
3 years ago
12

GIVING AWAY A LOT POINTS! PLEASE ANSWER!

Mathematics
1 answer:
masya89 [10]3 years ago
6 0

The slope of the line is “rise over run.” That’s the vertical change between the two points (the difference in the y-coordinates) divided by the horizontal change over the same segment (the difference in the x-coordinates).
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Solve for the variable x - 9 = 11
Strike441 [17]

Answer:

20

Step-by-step explanation:

x - 9 = 11

+9         +9

x = 20

3 0
2 years ago
Read 2 more answers
Which value of x makes the equation 1.25(6x - 20) = 50 true?
bixtya [17]
D. X = 10

6x-20= 40

6x=40+20

6x=60

X=10
4 0
2 years ago
A man jogs to the shop and back in half an hour on the way he jogs at 4m/s and on the way back he jogs at 5m/s ignoring time spe
pochemuha
Ratio 4:5
There are 9 total.
30 mins = 1800 secs. 
1800 divided by 9 = 200
200 secs = 3mins 20secs
200 is one "part" of the ratio, so multiply it by 4, then 5
800:1000
                           This is the important one
                                           V
13mins, 20secs: 16mins 40secs
Distance is speed x time,
16mins x 4 = 64
40 secs = 2/3
 x 4 = 1.6666
Distance to shop - 65.6m

5 0
3 years ago
What are the removable discontinuities of the following function? f (x) = StartFraction x squared minus 36 Over x cubed minus 36
jeyben [28]

Answer:

the removal discontinuity of the following function at x=-6 or x=6.

Step-by-step explanation:

factoring  f(x)  = (x - 6)(x + 6)

                         ----------------

                          x(x - 6)^x + 6)

3 0
2 years ago
Read 2 more answers
Colin is buying dirt to fill a garden bed that is a 9 ft by 16 ft rectangle. If he wants to fill it to a depth of 4 in., how man
timama [110]
Find the volume of the rectangular prism.

V = lwh

V = (9)(16)(4)

V = 756 ft^3

Convert to cubic yards:

1 ft^3 = 0.037037037 yd^3

756 * 0.037037037 = 28

So there are 28 cubic yards of dirt he needs.

Multiply this to 25 to find the total cost of the dirt:

28 * 25 = 700

So the project will cost $700
5 0
3 years ago
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