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3 years ago

GIVING AWAY A LOT POINTS! PLEASE ANSWER!

1 answer:

6 0

The slope of the line is “rise over run.” That’s the vertical change between the two points (the difference in the y-coordinates) divided by the horizontal change over the same segment (the difference in the x-coordinates).

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HELP ME ON THIS PLEASE!!!! SHOW WORK!!!!

Mumz [18]

Answer:

Step-by-step explanation:

ΔABC and ΔAJK are similar (AA). Therefore the sides are in proportion:

$\dfrac{AC}{AJ}=\dfrac{AB}{AK}$

We have:

AC = 1 + 4 = 5

AJ = 1

AB = 1 + x

AK = 1

Substitute:

$\dfrac{5}{1}=\dfrac{1+x}{1}$

$5=1+x$ <em>subtract 1 from both sides</em>

$4=x\to x=4$

ΔVUT and ΔVMN are similar (AA). Therefore the sides are in proportion:

$\dfrac{VU}{VM}=\dfrac{VT}{VN}$

We hve:

VU = x + 8

VM = x

VT = 49

VN = 49 - 14 = 35

Substitute:

$\dfrac{x+8}{x}=\dfrac{49}{35}$ <em>cross multiply</em>

$35(x+8)=49x$ <em>use the distributive property a(c + b) = ab + ac</em>

$35x+280=49x$ <em>subtract 35x from both sides</em>

$280=14x$ <em>divide both sides by 14</em>

$20=x\to x=20$

3 0

2 years ago

a ferry traveled 1/6 of the distance between two ports in 3/7 hour. The ferry travels at a constant rate.how much do the ferry t

Dahasolnce [82]

Answer:

1 hour = 7/18 of the distance between two ports

Step-by-step explanation:

Given that:

In 3/7 hours distance traveled is 1/6

For finding distance in one hour, divide both sides by 7/3 so that 3/7 would be cancelled out:

3/7 * 7/3 hours = 1/6 * 7/3 distance

By simplifying:

1 hour = 7/18 of the distance between two ports

This means that in one hour 7/18 of the distance is covered between two ports.

i hope it will help you!

8 0

3 years ago

Read 2 more answers

Help help help pls :)

kykrilka [37]

Answer:

$opposite\approx 70.02$

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

Please note that the names ( $opposite$ ) and ( $adjacent$ ) are subjective and change depending on the angle one uses in the ratio. However the name ( $hypotenuse$ ) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent ( $tan$ ) ratio.