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4 years ago

GIVING AWAY A LOT POINTS! PLEASE ANSWER!

1 answer:

6 0

The slope of the line is “rise over run.” That’s the vertical change between the two points (the difference in the y-coordinates) divided by the horizontal change over the same segment (the difference in the x-coordinates).

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Graph the line with the equation y=-2x + 6.

motikmotik

Answer:

can you show a link to the graph

Step-by-step explanation:

it will help me answer

8 0

3 years ago

3 + x, when the value of x is 15

lora16 [44]

Answer:

The answer is 18

Step-by-step explanation:

If you add 15 to 3 then you get 18

Hope this helps!!! :)

7 0

3 years ago

Read 2 more answers

MAKING BRAINLIEST!!Bruce Wayne splits his budget by using the ratio 12:7. For every $12 he spends

Anvisha [2.4K]

D. 28

this is because 48 divided by 12 is 4, 4 times 7 is 28.

3 0

3 years ago

Read 2 more answers

What is the value of c in the equation below? 2^-4(2^2)=a^b=c

Triss [41]

Answer:

The answer is option 4.

Step-by-step explanation:

You have to use Indices Law,

${a}^{m} \times {a}^{n} = {a}^{m + n}$

${a}^{ - n} = \frac{1}{ {a}^{n} }$

So for this question :

${2}^{ - 4} \times {2}^{2}$

$= {2}^{ - 4 + 2}$

$= {2}^{ - 2}$

${a}^{b} = c \\ c = {2}^{ - 2}$

$c = \frac{1}{ {2}^{2} }$

$c = \frac{1}{4}$

5 0

3 years ago

Need help

aleksandr82 [10.1K]

Using the normal distribution, the probabilities are given as follows:

a. 0.4602 = 46.02%.

b. 0.281 = 28.1%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

The parameters are given as follows:

$\mu = 959, \sigma = 263, n = 37, s = \frac{263}{\sqrt{37}} = 43.24$

Item a:

The probability is <u>one subtracted by the p-value of Z when X = 984</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{984 - 959}{263}$

Z = 0.1

Z = 0.1 has a p-value of 0.5398.

1 - 0.5398 = 0.4602.

Item b:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{984 - 959}{43.24}$

Z = 0.58

Z = 0.58 has a p-value of 0.7190.

1 - 0.719 = 0.281.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0

2 years ago