Answer:
Local minimum at x = 0.
Step-by-step explanation:
Local minimums occur when g'(x) = 0 and g"(x) > 0.
Local maximums occur when g'(x) = 0 and g"(x) < 0.
Set g'(x) equal to 0 and solve:
0 = 2x (x − 1)² (x + 1)²
x = 0, 1, or -1
Evaluate g"(x) at each point:
g"(0) = 2
g"(1) = 0
g"(-1) = 0
There is a local minimum at x = 0.
Step-by-step explanation:
Area of rectangle(A)=l×b
=4x×(x^2-2x+6)
= 4x^3-8x^2+24x
Answer:
(0,6)
Step-by-step explanation:
First, deal with the reflection. Reflecting the triangle over the x axis will reflect it vertically into the upper right quadrant. Because it is reflected vertically, the x values of the vertices will not change and the y values will be the negative of whatever value they are originally. If the coordinates of each vertex are (x,y), you can easily find their new location by changing it to (x,-y). After the reflection, the coordinates of the vertices are as follows:
A = (2,6) [originally (2,-6)]
B = (2,1) [originally (2,-1)]
C = (5,6) [originally (5,-6)]
Now, deal with the translation. A translation of -5 units horizontally means that the triangle will be moving 5 units to the left. The y values will be unaffected by the translation. To find the new coordinates, subtract 5 from the x values of the coordinates after the reflection.
A = (-3,6)
B = (-3,1)
C = (0,6)
Therefore, the answer is (0,6).
$76 is the answer
I hope this is the right answer
