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Bond [772]
3 years ago
11

How do you determine whether (6,2) is on the line y=1/2x+2

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
8 0

Answer:

If the point (6,2) does satisfy the equation, y = \frac{1}{2}x +2\\, the point is on the line. Otherwise it's not.

Step-by-step explanation:

Points that are on the line actually satisfy the equations of their respective lines. If the point (6,2) does satisfy the equation, y = \frac{1}{2}x +2\\, the point is on the line. Otherwise it's not.

Testing if (6,2) is on the line, y = \frac{1}{2}x +2\\:

y = \frac{1}{2}x +2 \\ 2 \stackrel{?}{=} \frac{1}{2}(6) +2 \\ 2 \stackrel{?}{=} 3 +2 \\ 2 \stackrel{?}{=} 3 +2 \\ 2 \stackrel{?}{=} 5 \\ 2 \neq 5

The point (6,2) does not satisfy the equation, y = \frac{1}{2}x +2\\, so the point is not on the line.

MariettaO [177]3 years ago
4 0

Answer:

Graph the line y=1/2x+2 then check the points.

Step-by-step explanation:

If I go on desmos, or just by hand and graph y=1/2x+2, I can see the points it goes through. Once I graph my equation, I will specifically type another coordinate "(6,2)" to see if it is directly in my line. For your equation, (6,2) is not in the line of y=1/2x+2.

I really hope this helps, ask anything else if needed.

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mihalych1998 [28]
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\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
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I=\textit{interest earned}\to &\$1\\
P=\textit{original amount deposited}\to& \$2\\
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t=years
\end{cases}
\\\\\\
1=2\cdot 0.10\cdot t\implies 1=0.2t\implies \quad \cfrac{1}{0.2}=t\implies 5=t
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3 years ago
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Step-by-step explanation:

3 0
3 years ago
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OLEGan [10]
Note: I'm assuming that your teacher wants you to use the approximation pi = 3.14
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Problem 1)

Plug the value r = 4.5 into the formula below to find the approximate volume

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Note: we can write "cubic cm" as "cm^3"
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The formula to use for the volume of a cylinder is
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V = pi*r^2*h
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Problem 3)

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3 0
3 years ago
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hope this helps :3

if it did pls mark brainliest

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Step-by-step explanation:

just did it on edge

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