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Step2247 [10]
3 years ago
12

Find the length of the third side to the nearest tenth

Mathematics
1 answer:
mylen [45]3 years ago
7 0

Answer:

a=6.9

Step-by-step explanation:

a(2)+4(2)=8(2)

4×4=16 8×8=64

16-16 64-16

a(2)=6.9

Caculator:

Press 2nd, press x2(close to bottom left)

6.92 PLEASE ROUND

6.92=6.9

a=6.9

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Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b
Ronch [10]
\32a^3b^2 \ , \  44ab^3 \ , \  40a^2b\\


\text {Taking out common factor : } \\ \\
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3 0
3 years ago
Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance
Feliz [49]

Answer:

9.5

Step-by-step explanation:

Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance.

Step 1

We find the Mean of the numbers

Mean = Sum of terms/ Number of terms

Mean = 9+12+9+14+6/5

= 50/5

= 10

Step 2

We find the sample variance

Formula =

(x - Mean)²/n - 1

n = 5

= (9 - 10)²+(12 -10)²+(9- 10)²+(14-10)²+(6-10)²/5 - 1

= 1+ 4+ 1+ 16+16/5 - 1

= 38/5 - 1

= 38/4

= 9.5

Therefore, Sample variance = 9.5

3 0
3 years ago
You decide to take your car on a drive through Canada, where gas is sold in liters and distances are measured in kilometers. Sup
12345 [234]

Answer:

the no of liters required is 50.55 liters

Step-by-step explanation:

Given that

The car gas efficiency is 23.0 mi/gal

distance is 495 km

1 gal = 3.78 L

1 km = 0.6214 mi

We need to find out the no of liters of gas that would needed to complete a trip

So,

= (495 × 3.78 × 0.6214) ÷ (23)

= 50.55 Liters

hence, the no of liters required is 50.55 liters

7 0
3 years ago
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