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nlexa [21]
3 years ago
6

Jamal is making two paintings using canvases that are similar rectangles. The length of the smaller canvas is 3 ft and the width

is 5 ft.
What is the length of the larger canvas if the width is 10 ft?
Mathematics
2 answers:
Alex787 [66]3 years ago
4 0
Let's start with what we know:

Smaller canvas:
Length (L_{1}) = 3ft
Width (W_{1}) = 5ft

Larger canvas:
Length (L_{2}) = ?
Width (W_{2}) = 10ft

Since these are similar rectangles, we can cross-multiply to calculate the missing length. Here's that formula:

\frac{ L_{1} }{ L_{2} } =  \frac{ W_{1} }{ W_{2} }
So let's plug it all in from above:

\frac{ 3 }{ L_{2} } = \frac{ 5 }{ 10 }
Now we cross multiply by multiplying the top-left by the bottom-right and vice versa:

(3)(10) = (5)(L_{2})
30 = 5L_{2}
Now divide each side by 5 to isolate L_{2}

\frac{30}{5} =  \frac{ 5L_{2}}{5}
The 5s on the right cancel out, leaving us with:

6 =  L_{2}

So the length of the larger canvas is 6 ft
tatuchka [14]3 years ago
4 0

It's not as complicated as you think. The smaller rectangle is 3ft with a width of 5ft. It's asking what the length of the larger canvas is if the width is 10ft. So you pretty much just do 10/5 which is 2 then you multiply 3ft by 2 and you get 6ft.

If you need any help just ask :)

-John

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