Answer:
1, 2, 3, 6,
Step-by-step explanation:
1*42
2*21 all = 42
3*14
6*7
Answer:
21+/-sqrt(253)=x
So one value for x is 21+sqrt(253)
and another is 21-sqrt(253)
Problem:
Given (21,7) and (x,1), find all x such that the distance between these two points is 17.
Step-by-step explanation:
Change in x is x-21
Change in y is 7-1=6
distance^2=(change in x)^2+(change in y)^2
17^2=(x-21)^2+(6)^2
289=(x-21)^2+36
Subtract 36 on both sides:
289-36=(x-21)^2
253=(x-21)^2
Take square root of both sides:
+/-sqrt(253)=x-21
Add 21 on both sides:
21+/-sqrt(253)=x
239.99 x 75%(75/100) ~ $180
$180 x 90%(90/100) = $162
The y-intercept, in this case, represents when x is at 0, or when she just began observing.
Ok, ranked by axis of symmetry
basically x=something is the axis of symmetry
the way to find the axis of symmetry is to convert to vertex form and find h and that's the axis of symmetry
but there's an easier way
for f(x)=ax^2+bx+c
the axis of symmetry is x=-b/2a
nice hack my teacher taught me
so
f(x)=3x^2+0x+0
axis of symmetry is -0/(3*2), so x=0 is the axis of symmetry for f(x)
g(x)=1x^2-4x+5,
axis of symmetry is -(-4)/(2*1)=4/2=2, x=2 is axis of symmetry for g(x)
h(x)=-2x^2+4x+1
axis of symmetry is -4/(2*-2)=-4/-4=1, x=1 is the axis of symmetry for h(x)
0<1<2
axisies
f(x)<h(x)<g(x)
order based on their axises of symmetry is f(x), h(x), g(x)
