Match the system of equations with their solution

Mrs. Kim is teaching a 5th grade class. She is standing 48 feet in front of Lester. Carey is sitting to Lester's right. If Carey

victus00 [196]

Lester and Carey are 14 feet apart

Step-by-step explanation:

Mrs. Kim is teaching a 5th grade class

She is standing 48 feet in front of Lester
Carey is sitting to Lester's right
Carey and Mrs. Kim are 50 feet apart

We need to find how far apart Lester and Carey

Look to the attached figure

The positions of Mrs. Kim, Lester, and Carey formed a right triangle

∵ The distance between Mrs. Kim and Carey is 50 feet

∴ The length of the hypotenuse of the Δ = 50 feet

∵ The distance between Mrs. Kim and Lester is 48 feet

∴ The length of one leg of the Δ = 48 feet

The formula of length of the sides of the right Δ is:

$(hypotenuse)^{2}=(leg_{1})^{2}+(leg_{2})^{2}$

Substitute the length of the hypotenuse and the length of the given leg in the formula above

∵ (50)² = (48)² + (leg)²

∴ 2500 = 2304 + (leg)²

- Subtract 2304 from both sides

∴ 196 = (leg)²

- Take square for both sides

∴ 14 = leg

∵ This leg represents the distance between Lester and Carey

∴ The distance between Lester and Carey = 14 feet

Lester and Carey are 14 feet apart

Learn more:

You can learn more about the right triangle in brainly.com/question/1238144

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8 0

3 years ago

Men are believed to have a slightly longer average length of short hospital stays than women; 5.2 days versus 4.5 days respectiv

Georgia [21]

Answer:

Since our calculated value is lower than our critical value, $z_{calc}=2.02$ , we have enough evidence to FAIL to reject the null hypothesis at 1% of singificance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

Step-by-step explanation:

1) Data given and notation

$\bar X_{1}=5.2$ represent the mean for group men

$\bar X_{2}=4.5$ represent the mean for group women

Assuming these values for the remaining data:

$\sigma_{1}=1.2$ represent the population standard deviation for the sample men

$\sigma_{2}=1.5$ represent the population standard deviation for the sample women

$n_{1}=32$ sample size for the group men

$n_{2}=30$ sample size for the group women

z would represent the statistic (variable of interest)

$p_v$ represent the p value

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for men it's higher than the mean for women, the system of hypothesis would be:

H0: $\mu_{1} \leq \mu_{2}$

H1: $\mu_{1} > \mu_{2}$

If we analyze the size for the samples both are higher than 30, and we know the population deviation's, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

We have all in order to replace in formula (1) like this:

$z=\frac{5.2-4.5}{\sqrt{\frac{1.2^2}{32}+\frac{1.5^2}{30}}}=2.02$

4) Find the critical value

In order to find the critical value we need to take in count that we are conducting a right tailed test, so we are looking on the normal standard distribution a value that accumulats 0.01 of the area on the right and 0.99 of the area on the left. We can us excel or a table to find it, for example the code in Excel is:

"=NORM.INV(1-0.01,0,1)", and we got $z_{critical}=2.33$

5) Statistical decision

Since our calculated value is lower than our critical value, $z_{calc}=2.02$ , we have enough evidence to FAIL to reject the null hypothesis at 1% of significance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

6 0

3 years ago

Whats the squareroot of 18

andreev551 [17]

Answer:

it should be 4.24264068712 looked it up

4 0

2 years ago

Read 2 more answers

PLEASE HURRY I'M BEING TIMED

kobusy [5.1K]

Answer: