Evaluate the expression 120n + 160,500 when n =32.
2 answers:
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Answer:
The standard error is 11.
Step-by-step explanation:
Given : If the standard deviation of a normally distributed population is 22.0 and we take a sample of size 4.
To find : The standard error ?
Solution :
The standard error formula is
Where, is the standard deviation of a normally distributed population
n=4 is the sample size
Substitute the value,
Therefore, the standard error is 11.