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matrenka [14]
3 years ago
8

Which number would be 16,000 when rounded to the nearest thousand: 15,472 or 15,518 or 16,511 or 16,739?

Mathematics
2 answers:
Anna11 [10]3 years ago
7 0
15,518, because it is over 15,500 and below 16,499.999999...
Likurg_2 [28]3 years ago
5 0
The answer his 15,518. 

  Why?

1.Beacause, 15,518 doesn't go over 16,000.

 2.15,518 his kinda half of 16,000 if you take away 18!
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I need help on this plz
Fantom [35]
I’m timed on this I need help as well
4 0
3 years ago
Given the system of linear equations:
ruslelena [56]
6x+7y=32 and 2x+5y=16

if you add the two equations you get the first answer and if you subtract the two equations you get the second answer
3 0
2 years ago
Which of the following is not a rational number?A)22 B) ⅓ C)―16 D) 0.343
Zigmanuir [339]
Its 0.343 because it cannot be expressed as a fraction or whole number
4 0
3 years ago
Bulan rows on a crew team. Her team rows their boat at a split (rate) of 2 min/500 m.
notka56 [123]

Answer:

250

Step-by-step explanation:

If Bulan's team rows their boat at a rate of

2

minutes per

500

meters, they row at a rate of

1

minute per

250

meters. We know this because

1

minute is

1

2

of

2

minutes, and in this time, they will have to have rowed

1

2

the distance they would row in

2

minutes (

500

m).

1

2

of

500

is

250

.

So, we now have the rate in min/m.

If, every

1

minute, Bulan's team rows

250

meters, this means that every

250

meters, they have rowed for

1

minute.

Bulan's team's rowing rate in m/min is

250

m/

1

min.

8 0
3 years ago
Read 2 more answers
What are the potential solutions to the equation 2ln(x+3)=0
skad [1K]
2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1

Expanding the left side gives

x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0

which gives two solutions, x=-4 and x=-2. But if x=-4, then \ln(x+3)=\ln(-1), but this number isn't real, so x=-4 is an extraneous solution. Meanwhile if x=-2, you get \ln(-2+3)=\ln1=0, so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
4 0
3 years ago
Read 2 more answers
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