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MatroZZZ [7]
3 years ago
15

Convert the equation -9x^2+25y^2-100y-125=0 into standard form​

Mathematics
2 answers:
Rudiy273 years ago
5 0

Answer:

(y−2)29−x225=1

Step-by-step explanation:

vladimir1956 [14]3 years ago
4 0

Answer:

(y-2)^2/9-x^2/25=1

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What is the answer? HELP!
victus00 [196]
They are not congruent 

4 0
3 years ago
By how many degrees did the direction of the boat change
gulaghasi [49]

Answer:

The boat turned <u>39°</u> degrees when it made its first turn.

Step-by-step explanation:

The question is as following:

A boat traveled north for 28 miles, then tuned x° south west and traveled for 25 miles before stopping. When it stopped, the boat was 18 miles from its starting point.

By how many degrees did the direction of the boat change when it made its first turn? Round to the nearest degree.

===================================================

See the attached figure which represent explanation of the problem.

The boat start from point A to point B then stopped at point C

AB = 28 miles, BC = 25 miles and AC = 18 miles.

It is required to find the angle x

By applying the cosine Rule:

AC² = AB² + BC² - 2 * AB * BC * cos x

18² = 28² + 25² - 2 * 28 * 25 * cos x

2 * 28 * 25 * cos x = 28² + 25² - 18²

1400 cos x = 1085

Cos x = 1085/1400 = 0.775

x = Cos⁻¹ 0.775 = 39.2° = 39° to the nearest degree.

So, the boat turned <u>39°</u> degrees when it made its first turn.

8 0
3 years ago
Which of the following has eight faces? A. Icosahedron B. Octahedron C. Dodecahedron D. Tetrahedron
Stels [109]
Octahedron has eight faces.
6 0
3 years ago
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Which ordered pair describes the location of point A? (-6, 5) (-6, -5) (5, -6) (5, 6)
Neko [114]

Answer:

the answer is -6,5

Step-by-step explanation:

just look at the left side ( the x axis )first then right(the y axis)

8 0
3 years ago
Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
3 years ago
Read 2 more answers
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