For this problem, you would have to use a system of equations. Hope this helps!
5). Radius = 6 km. Circumference = 12π km. Area = 36π km²
6). Diameter = 8 mm. Circumference = 8π mm. Area = 16π mm²
Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.
g100num [7]
<span>1. If it is intersection then it SHOULD be included in both the sets right?
Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!!
So
A={51,53,57,59,61......99}
B={55,60,65,70.......95} [We stop till 100 because set A has no such element]
So what is A ∩ B here?
A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}
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Answer:
first one is A and the second one is B.
Step-by-step explanation:
First, calculate 18% of 23.
23 x 0.18 = 4.14
Then, add this value (the increase) to the original value of 23.
23 + 4.14 = 27.14
Rounding off, we get 27.
