There are many ways to check if the point (1,3) is a solution to the linear equation
.
Let us check it by expressing y in terms of x.
The given expression is 5x-9y=32. If we add -5x to both sides we will get:
![-9y=-5x+32](https://tex.z-dn.net/?f=%20-9y%3D-5x%2B32%20)
Multiplying both sides by -1 we will get:
![9y=5x-32](https://tex.z-dn.net/?f=%209y%3D5x-32%20)
In order to isolate y, we will divide both sides by 9 to get:
![y=\frac{5}{9}x-\frac{32}{9}](https://tex.z-dn.net/?f=%20y%3D%5Cfrac%7B5%7D%7B9%7Dx-%5Cfrac%7B32%7D%7B9%7D%20%20%20)
Now let us plug in the given value of x=1 from the point (1,3). This should give us y=3. Let us see if we get y=3 when we plug x=1 in the above equation.
![y=\frac{5}{9}\times 1-\frac{32}{9}=\frac{5-32}{9}](https://tex.z-dn.net/?f=%20y%3D%5Cfrac%7B5%7D%7B9%7D%5Ctimes%201-%5Cfrac%7B32%7D%7B9%7D%3D%5Cfrac%7B5-32%7D%7B9%7D%20%20)
![\therefore y=\frac{-27}{9}=-3](https://tex.z-dn.net/?f=%20%5Ctherefore%20y%3D%5Cfrac%7B-27%7D%7B9%7D%3D-3%20%20)
Thus, we see that when x=1, y=-3 and that
and hence we conclude that the point (1,3) is not a solution to the original given linear equation 5x-9y=32.
For a better understanding of the explanation given here a graph has been attached. As can be seen from the graph, (1,3) does not lie on the straight line that represents 5x-9y=32, but (1,-3) does lie on it as we had just found out.
Answer:
2
Step-by-step explanation:
Answer:
![mn + 5m - 2 + mn + 3 \\ = 2mn + 5m + 1 \\ = = = = = = = = = = =](https://tex.z-dn.net/?f=mn%20%2B%205m%20-%202%20%2B%20mn%20%2B%203%20%5C%5C%20%20%3D%202mn%20%2B%205m%20%2B%201%20%5C%5C%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20%20%3D%20)
<h2>HOPE U UNDERSTOOD</h2>
PLEASE MARK AS BRAINLIEST ONE✌
ALL THE BEST FOR YOU
COMMENT PLEASE FOR ANY DOUBTS.