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Sunny_sXe [5.5K]
3 years ago
6

What is the measure of angle x, help

Mathematics
2 answers:
blondinia [14]3 years ago
7 0
Y=180-51-56
=73
x=180-72-73
=35°
Sergeeva-Olga [200]3 years ago
4 0
Y = 180 - 51 -56 = 73

x = 180 - 73 - 72 = 35

x = 35 degrees
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Simplify this expression<br> 4x(7x^2)<br> A 11x^2<br> B. 28x^2<br> C. 11x^3<br> D. 28x^3
slega [8]

Answer:

28 x^3

Step-by-step explanation:

4x(7x^2)

4 * x* 7* x*x

4*7   x*x*x

28 x^3

7 0
3 years ago
Read 2 more answers
What is the mean?<br> 1 6 1 10 5 5 7
algol13

Answer:

5

Step-by-step explanation:

if u add al of these it equals 35 divided by 7 equals 5

7 0
3 years ago
The graph shows the height of a hiker above sea level.
dimaraw [331]

The <u>correct answer</u> is:


B) The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is walking up a gentle slope. Flat parts of the graph show where the elevation does not change, which means the trail is flat here. The steep part at the end of the graph shows that the hiker is descending a steep incline.


Explanation:


The variables are marked on the graph. Time is marked along the x-axis, which means it is the independent variable. Height is marked along the y-axis, which means it is the dependent variable.


The first part of the graph rises slowly. This means the elevation does not change much over the time; this would be consistent with a gentle slope being climbed.


The flat areas are where the elevation does not change. This would be consistent with the hiker resting.


The steep decrease at the end shows that the elevation goes down quickly. This is consistent with the hiker climbing down a steep slope.

3 0
3 years ago
Read 2 more answers
A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.41 mpa and a sample standa
nignag [31]

For this problem, the confidence interval is the one we are looking for. Since the confidence level is not given, we assume that it is 95%.

 

The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n


Where:

<span>
</span>

α= 5%


α/2 = 2.5%


t 0.025, 19 = 2.093 (check t table)


n = 20


df = n – 1 = 20 – 1 = 19

So plugging in our values:


8.41 ± 2.093 * 0.77 √ 1 + 1/20


= 8.41 ± 2.093 * 0.77 (1.0247)


= 8.41 ± 2.093 * 0.789019


= 8.41 ± 1.65141676


<span>= 6.7586 < x < 10.0614</span>

3 0
3 years ago
Two fifths of one less than a number is less than three fifths of one more than that number .what numbers are in the solution se
Lelechka [254]

2/5(x - 1) < 3/5(1 + x)

To find the solution, we can use the distributive property to simplify.

2/5x - 2/5 < 3/5 + 3/5x

Multiply all terms by 5.

2x - 2 < 3 + 3x

Subtract 2x from both sides.

-2 < 3 + x

Subtract 3 from both sides.

-5 < x

<h3><u>The value of x is greater than the value of -5.</u></h3>
5 0
3 years ago
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