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ivanzaharov [21]
3 years ago
15

The temperature at noon was -30C.By 10.P.M. on the same day the temperature decreased by 5.50. What is the temperature at 10 P.M

?
-8.40C

-5.40C

-2.40C

1.60C
Mathematics
2 answers:
Nata [24]3 years ago
6 0

Answer:

Step-by-step explanation:

Anna [14]3 years ago
6 0
Bxhxyfdvbsghx dhdvdgdb Fuchs.
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What is the product? 2y/y-3 multiply 4y-12/2y+6
Scrat [10]

Answer: the answer is attached

Step-by-step explanation:

2y/y-3. 4y-12/2y+6

Download docx
4 0
3 years ago
Find the measure of an angle whose supplement measures seventeen times its measure
Lilit [14]
<span>supplement angles, sum = 180
lets x =  angle
</span><span>its supplement = 180 - x

x + 17x = 180
18x = 180
x = 10
180 -10 = 170

answer
angle = 10
its </span><span>supplement  = 170</span>
5 0
3 years ago
The least-squares regression line is_____________. A. the line that passes through the most data points.B. the line that makes t
Elanso [62]

Answer:

<h3>The option B) is correct.</h3><h3>That is the line that makes the sum of the squares of the vertical distances of the data points from the line (the sum of squared residuals) as small as possible is correct answer</h3>

Step-by-step explanation:

Given that " The least-squares regression line "

The least-squares regression line is <u>the line that makes the sum of the squares of the vertical distances of the data points from the line (the sum of squared residuals) as small as possible.</u>

Therefore option B) is correct

3 0
3 years ago
Simplify. final answer should be written in standard form (a+b)(3a-b)(2a+7b)
algol13

we have

(a+b)(3a-b)(2a+7b)

step 1

Solve

apply distributive property

(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2

step 2

Multiply (3a^2-4ab-b^2) by (2a+7b)

6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3

answer is

<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
6 0
1 year ago
The low temperatures for a week in winter were -2° F, -15° F, -7° F, 1° F, -4° F, 5° F, 8° F. What was the average low
Novay_Z [31]

Answer: -2 F

Step-by-step explanation:

To find the average, or <em>mean, </em>of a data set, you must first combine all of the values in the set. Since some of these values are negative, it seems more difficult to solve. But it isn't. To find the mean of any data sets, you can find the absolute value of each numerical value. If you combine these regularly, it would be -15, but that is incorrect. The answer is -2 because some of the values may be negative, but you can find the answer easily. Just remember: To find the mean of data sets with negative values, you can find their absolute values, and solve from there. If this does not work for you, then find another solution. But the correct answer is -2 F.

3 0
3 years ago
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