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2 years ago

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A metalworker has a metal alloy that is 20% copper and another alloy that is 65% copper. How many kilograms of each alloy shou

ld the metalworker combine to create 100 kg of a 56% copper alloy?
The metalworker should use _kilograms of the metal alloy that is 20% copper and _kilograms of the metal alloy that is 65% copper.
(Type whole numbers.)

1 answer:

sweet-ann [11.9K]2 years ago

8 0

Answer:

The metallurgist must use 20 kilograms of the metal alloy which is 20% copper and 80 kilograms of the metal alloy which is 65% copper.

Step-by-step explanation:

We call the alloy 20% copper.

We call the alloy 65% copper.

Let's call the new version you want to create.

When mixing the M Alloy with the S you want to obtain 100 kg of the new alloy

$M + S = 100$ (i)

Then

$0.2M + 0.65S = 100(0.56)$ (ii)

We substitute (i) in (ii)

$0.2(100-S) + 0.65S = 100(0.56)$

$20 - 0.2S + 0.65S = 56$

$0.45S = 36$

$S = \frac{36}{0.45}$

$S = 80 kg$ (iii)

Now we substitute (iii) in (i)

$M + 80 = 100$

$M = 20$

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