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-BARSIC- [3]
3 years ago
11

A woman bought 70 Cubesof Sugar and Sold 25% ofthem.How many Cubes is sheLeft with?​

Mathematics
2 answers:
damaskus [11]3 years ago
5 0

Answer:

52.5 cubes

Step-by-step explanation:

100-25=75

100%=70

75%=x

75 x 70=5250/100=52.5 cubes

ser-zykov [4K]3 years ago
4 0

Answer:

Briainliest here

Step-by-step explanation:

there is 70 cubes of sugar

now 25% is sold

70 x 75% = 70 x 0.75 = 52.5

(I did 75% insted of -25% because its and it actualy works!

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16y5+4y5-12y3+15y3?<br> What is the simplified form?
Eddi Din [679]

Answer:

20y^5+3y^3

Step-by-step explanation:

16y^5 + 4y^5 -12y^3 + 15y^3

All we can do here is combine like terms (add those that have the same the same exponent)

20y^5+3y^3

Good luck!

3 0
3 years ago
Read 2 more answers
There are two flavors of ice cream; strawberry and chocolate. the amount of strawberry ice cream is in the shape of a sphere. th
amid [387]
The complete question is
<span>There are two flavors of ice cream; strawberry and chocolate. the amount of strawberry ice cream is in the shape of a sphere. the amount of chocolate ice cream fills the rest of the cone. the dimensions of the sphere is 6cm and the cone is 12cm.

the figure is not drawn to scale  

A. what is the volume, in cubic centimeters of the right circular cone ?show or explain how you got your answer.
B. the amount of strawberry ice cream is in the shape of a sphere. what is the volume in cubic centimeters of the strawberry ice cream?
C. what is the total volume in cubic centimeters of all the ice creams?
D.the amount of chocolate ice cream fills the rest of the cone. what is the volume in cubic centimeters of the chocolate ice cream?  

we know that
the height of the cone is 12 cm
the diameter of a cone is 6 cm

Part A) </span>what is the volume, in cubic centimeters of the right circular cone? show or explain how you got your answer.

we know that
the volume of a cone=(1/3)*pi*r²*h
r=6/2----> 3 cm
h=12 cm
The volume of a cone=(1/3)*pi*3²*12------> 36*pi cm³-------> 113.04 cm³

the answer part A) is 36*pi cm³  (113.04 cm³)

Part B) the amount of strawberry ice cream is in the shape of a sphere. what is the volume in cubic centimeters of the strawberry ice cream?
volume of a sphere=(4/3)*pi*r³
r=3 cm
volume of a sphere=(4/3)*pi*3³-----> 36*pi cm³------> 113.04 cm³

the answer part B) is 36*pi cm³  (113.04 cm³)

Part C) what is the total volume in cubic centimeters of all the ice creams?
volume of the cone+volume of a hemisphere

36*pi+18*pi-----> 54*pi cm³-------> 169.56 cm³

the answer Part C) is 54*pi cm³ (169.56 cm³)

Part D) .the amount of chocolate ice cream fills the rest of the cone. what is the volume in cubic centimeters of the chocolate ice cream?
volume of a cone-volume of a hemisphere
36*pi-18*pi-----> 18*pi cm³-----> 56.52 cm³

the answer Part D) is 18*pi cm³ (56.52 cm³)

5 0
3 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
Write the product as a sum: 14cos(39x)sin(19x)
charle [14.2K]

Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

sin(<em>a</em> - <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) - cos(<em>a</em>) sin(<em>b</em>)

Adding these together gives

sin(<em>a</em> + <em>b</em>) + sin(<em>a</em> - <em>b</em>) = 2 sin(<em>a</em>) cos(<em>b</em>)

To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) - sin(20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

4 0
2 years ago
Question in pic! help asap!! will give brainliest!!
Ne4ueva [31]
11,340 I believe. 5% of 8400 is 420. 420*7=2940 2940+8400=11340
7 0
2 years ago
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