Please help! I really need this other wise I’m going to fail! I can’t figure it out!

Suzette ran and biked for a total of 34 mi in 3.5 h. Her average running speed was 6 mph and her average biking speed was 12.5 m

olga nikolaevna [1]

Answer:

From the information given

x is time for which she ran at speed of 6mi/h and

y is time for which she biked at speed of 12.5 mi/h

total time = 3.5 h

total distance = 34 mi

so

6x + 12.5y = 34 and

x + y = 3.5

x = 3.5 - y

6 ( 3.5 - y) + y = 34

6.5y = 13 which gives

y = 2 and this

x = 1.5

so suze ran for 1.5 h and biked for 2 h

CHECK

speed of run X time of run + speed of biking x time of biking must be = total distance covered

6 × 1.5 + 12.5 × 2 = 9 + 25= 34 mi

which is true

8 0

3 years ago

What is the axis of symmetry of -2x^2+12x-3

Zanzabum

Answer:

x = 3

Step-by-step explanation:

The formula for the axis of symmetry is x = -b/(2a).

Here, a = -2 and b = 12, so the axis of symmetry is

-12

x = --------- = 3 => x = 3

2(-2)

3 0

3 years ago

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

- 1/6 [ 3 - 15 (1/2)2]

bonufazy [111]

Answer:

Your answer is -2

Step-by-step explanation:

1/6 [ 3 - 15 1/2 x 2 ] = -2/1 = -2

Hope this helps : )

8 0

2 years ago

Select the BEST classification for square root .0081 . A) irrational B) rational C) imaginary D) complex

Reika [66]

Answer:

B) Rational

Step-by-step explanation:

The square root of .0081 is .09, which is a very real number

6 0

3 years ago

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