All categories

2 years ago

Determine what type of model best fits the given situation:

1 answer:

3 0

If we imagine an x-axis as the time and y-axis as the temperature. The change in y is -5 when the change in x is 20. This ratio then is -5/20, or -1/4 when simplified. Because it is a constant non changing slope, the model can be described as linear.

You might be interested in

Show that if A is invertible, then det Upper A Superscript negative 1det A−1equals=StartFraction 1 Over det Upper A EndFraction

netineya [11]

Answer:

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

Step-by-step explanation:

Remember that if

$I$ = Identity Matrix

then $det(I)=1$ .

Also remember that for any invertible matrix

$A*A^{-1} = I =$ Identity Matrix.

Therefore

$det(A*A^{-1}) = det(A)*det(A^{-1}) = det(I) = 1$

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

7 0

3 years ago

Whats 8 2.5% of 75?Write your answer as a decimal.

Katena32 [7]

216 % hope this helps !!

4 0

3 years ago

Read 2 more answers

+<br> What is the answer

padilas [110]

The answer is edition

8 0

3 years ago

In the accompanying diagram, parallelogram ABCD has

Taya2010 [7]

Answer:

The area of the paralellogram is 24 square units.

Step-by-step explanation:

Geometrically speaking, the area of the parallelogram has an equation equivalent to the area formula for a rectangle, that is:

$A = b\cdot h$ (1)

Where:

$A$ - Area.

$b$ - Base.

$h$ - Height.

The base and height of the parallelogram are, respectively:

Base

$b = 8-2$

$b = 6$

Height

$h = 5-1$

$h = 4$

Then, the area of the parallelogram is:

$A = (6)\cdot (4)$

$A = 24$

The area of the paralellogram is 24 square units.

5 0

3 years ago

Find the equation of the line through (-9,6) that is perpendicular to the line through (7,8),

Setler [38]

Step-by-step explanation:

I assume as "equation" we mean the slope-intercept form :

y = ax + b

"a" is the slope of the line (y coordinate change / x coordinate change when going from one point to another on the line). b is the y-intercept (the y value when x = 0).

we get the slope by finding the perpendicular slope of the first line.

the slope of the first line when going from (-3, -9) to (7, 8) :

x changes by + 10 (from -3 to +7).

y changes by + 17 (from -9 to +8).

so, that slope is 17/10.

the perpendicular slope is turning the original slope upside-down and flips the sign :

-10/17

so, a = -10/17

now, as we have only the slope and a point of the new line, we can use the point-slope form to stay and then transfer into the slope-intercept form.

y - y1 = a(x - x1)

where "a" is again the slope, and (x1, y1) is a point on the line

y - -6 = -10/17 × (x - -9)

y + 6 = -10/17 × (x + 9) = -10/17 × x - 90/17

y = -10/17 × x - 90/17 - 6 =

= -10/17 × x - 90/17 - 102/17 =

= -10/17 × x - 192/17

so, the equation is (in a maybe nicer way)

y = -1/17 × (10x + 192)

7 0

1 year ago