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3 years ago

Correct and smartest answer gets brainliest and full ratings. :)

Mathematics

2 answers:

Naddik [55]3 years ago

8 0

The answer is C) y=-5/2x-3

anygoal [31]3 years ago

3 0

If 2 lines are perpendicular then the product of their slopes will be -1

so 2/5 * m = -1 where m is the slope of the line

m = -1 / 2/5 = -5/2

It's C

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

A picture is mounted on a frame measuring 25 centimeters by

makvit [3.9K]

Answer:

I think it's 1,125 and 4485

Step-by-step explanation:

25x13x3

115x13x3

3 0

3 years ago

A landscaper builds a regular hexagonal patio in a circular garden. The area not covered by the patio will be covered in grass.

Taya2010 [7]

The area that's covered by the grass will be 7.065m²

The area of a circle is found by using the formula: = πr²

where, r = radius = 1.5m

π = 3.14

Therefore, to solve the question, we'll slot the value of the radius into the formula and this will be:

Area = πr².

Area = 3.14 × 1.5²

Area = 3.14 × 1.5 × 1.5

Area = 7.065m²

In conclusion, the area is 7.065m²

Read related link on:

brainly.com/question/24705421

7 0

3 years ago

bath walked 10 7/8 miles one week she walk 2 1/4 fewer miles the following week about how many miles did she walk the second wee

bagirrra123 [75]

Answer:

8 and 5/8

Step-by-step explanation:

The question is just subtraction of fractions. First, you subtract the whole numbers. 10-2=8. Then you subtract the fractions. To do this, you have to make them equivalent. Just multiply the 1/4 by 2 and you get 2/8. Now, 7/8 - 2/8 = 5/8. Your final answer is 8 and 5/8

7 0

3 years ago

What is 3h^2+6h-18x as a product of two factors?? Please help,*a lot of points*

Vaselesa [24]

-3 is one of them hope this helps

4 0

3 years ago