What is 3h^2+6h-18x as a product of two factors?? Please help,*a lot of points*
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
The diagonals of a rhombus are perpendicular, so ∠AED = 90° and ∠BEC = 90°.
∠DAE = 180° - ∠AED - ∠EDA = 180° - 90° - 35° = 55°
BD is a transversal across parallel sides AD and BC, so ∠EBC = ∠EDA = 35°.
∠BCE = 180° - ∠BEC - ∠EBC = 180° - 90° - 35° = 55°
