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skelet666 [1.2K]
2 years ago
15

Solve the system of equations by substitution.

Mathematics
1 answer:
mojhsa [17]2 years ago
6 0

Answer:

6 = −4x + y

−5x − y = 21  

Answer:  (-3, -6)


2x + y = 20 6x – 5y = 12  

Answer:

(7 , 6)


Step-by-step explanation:

Solve the system of equations by substitution.

6 = −4x + y --> y = 4x + 6

−5x − y = 21

Substitute y = 4x + 6 into −5x − y = 21

−5x − (4x + 6) = 21

-5x - 4x - 6 = 21

-9x = 27

  x = - 3

y = 4(-3) + 6

y = -12 + 6

y = -6

(-3, -6)


Solve the system by the elimination method.

2x + y = 20

multiply the equation by (-3) ; 2x + y = 20  so

-6x - 3y = - 60

6x – 5y = 12

------------------add

-8y = - 48

  y = 6

2x + y = 20

2x + 6 = 20

2x = 14

 x = 7

(7 , 6)

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Answer:

The highest possible average is 348

Step-by-step explanation:

we know that

No more than 60 means -----> maximum 60 ( less than or equal to 60)

To find the possible average using proportion

Remember that the average is the number of hits in 1,000 times at bat

If the average is 300 with maximum 60 times at bat

then

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If the player gets 5 hits in her next 6 times at bat

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Find out the average

Let

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\frac{66}{23}=\frac{1,000}{x}\\\\x=23*1,000/66\\\\x=348

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Can I get help with these 2 problems?
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2 years ago
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I will give brainliest to simplest explanation! There are 2 Senators from each of 50 states. We wish to make a 3-Senator committ
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Answer:

117,600 ways

Step-by-step explanation:

This problem can be solved using fundamental principle of counting , according to which , if there are m different things and n different things,

then there m*n ways to combine.

Example: if there 5 shirts and 3 ties,

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____________________________________

In the problem,\

number of states is 50,

let those states be

A1, A2, A3, A4 ......A50

in each state there are 2 senate

Condition

3-Senator committee in which no two members are from the same state.

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hence first member can be chosen in 50 ways

for simplicity lets take state A1, you can choose any one you wish

second member cannot be from state A1, then number of state left = 49

second member can be chosen from  any of 49 state left

hence second member can be chosen in 49 ways

for simplicity lets take state A2,

Third member cannot be from state A1 and A2, then number of state left = 48

Third member can be chosen from  any of 48 state left

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3 years ago
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Answer:

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Step-by-step explanation:

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Now, making the graph we will plot

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Answer:

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Step-by-step explanation:

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