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Sergio [31]
3 years ago
9

I need help ~~~~~ Hggffv

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0
For a question like this, order of operations must be followed. This can be expressed with PEMDAS.

P arenthesis
E xponents
M ultiplication
D ivision
A ddition
S ubtraction

8^2 ÷ 4 + 3.7(42.3-24.6) -------> Parenthesis first
8^2 ÷ 4 + 3.7(17.7) ------> Now exponents
64 ÷ 4 + 3.7(17.7) ------> Now multiplication and division
16 + 65.49 --------> And finally addition
81.49 which is answer choice C
I hope this helps!

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Clara has 8 coins worth 17¢. if the coins are all dimes and pennies, how many dimes and pennies does she have?
Sliva [168]
Let x = the number of dimes
Let y =  the number of pennies.

There are 8 coins, therefore
x + y = 8        (1)

The coins are worth 17 cents, therefore
10x + y = 17     (2)

Subtract equation (1) from equation (2).
10x + y - (x + y) = 17 - 8
9x = 9
x = 1

From (1), obtain
y = 8 -x = 8 - 1 = 7

Answer: 1 dime, 7 pennies.

4 0
3 years ago
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valentina_108 [34]
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6 0
3 years ago
What is the smallest solution to the equation 2/3 x^2=24
True [87]

Answer:

The smallest solution is -6

Step-by-step explanation:

2/3 x^2=24

Multiply by 3/2 on each side

3/2 *2/3 x^2=24 *3/2

x^2 = 36

Take the square root of each side

sqrt(x^2) = ±sqrt(36)

x = ±6

x = -6, 6

The smallest solution is -6

7 0
3 years ago
In a group of eighteen people, each person shakes hands once with each other person in the group. How many handshakes will occur
miv72 [106K]

The number of handshakes that will occur in a group of eighteen people if each person shakes hands once with each other person in the group is 153 handshakes

In order to determine the number of handshakes that will occur among 18 people, that is, the number of ways we can choose 2 persons from 18 people.

∴ The number of handshakes = ^{18}C_{2}

^{18}C_{2} = \frac{18!}{(18-2)!2!}

^{18}C_{2} = \frac{18!}{16!2!}

^{18}C_{2} = \frac{18\times17\times16!}{16!\times2!}

^{18}C_{2} = \frac{18\times17}{2\times1}

^{18}C_{2} = \frac{306}{2}

^{18}C_{2} = 153

∴ The number of handshakes = 153 handshakes

Hence. 153 handshakes will occur in a group of eighteen people if each person shakes hands once with each other person in the group.

Learn more here: brainly.com/question/1991469

5 0
2 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s
Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that \mu = 1262, \sigma = 118

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

Z = \frac{X - \mu}{\sigma}

-0.643 = \frac{X - 1262}{118}

X - 1262 = -0.643*118

X = 1186

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 1262}{118}

X - 1262 = -1.96*118

X = 1031

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 1262}{118}

X - 1262 = 1.96*118

X = 1493

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 1262}{118}

X - 1262 = -0.675*118

X = 1182

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 1262}{118}

X - 1262 = 0.675*118

X = 1342

IQR:

1342 - 1182 = 160

7 0
3 years ago
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