Just count the amount of each letter and write it as a exponent = 3x²y³
First is B, since 1 and 3 are corresponding angles, they must be equal
Next is I, 3 and 5 must be equal since they are vertically opposite
Last is transitive property
Since 1 = 3 and 3 = 5, then 1 must equal 5
Look at the picture.
The formula of an area of a triangle:

In the equilateral triangle, the measures of all angles are the same and equal to 60°.
Therefore your answer is:

Answer:
There should be at most 24 lucky numbers in the third bag.
Step-by-step explanation:
Initially, there are 200 numbers. Two bags with 100 each. There are 31+18 = 49 lucky numbers. So there is a 49/200 = 0.245 probability that a randomly selected number from a random bag is the lucky number.
Now with 300 numbers, we want this probability to be lower than 24.5%. So we should solve the following rule of three:
200 - 49
300 - x



With the third bag, the probability will be the same if 73.5-49 = 24.5 lucky numbers are added. So there should be at most 24 lucky numbers in the third bag.