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Butoxors [25]
4 years ago
5

Which answer choice would it be and why

Mathematics
2 answers:
Anastaziya [24]4 years ago
7 0
3.2a-4.3b-(1.4a-3.9b+1.2) multiply contents of brackets on a negative sign. So, 3.2a-4.3b-1.4a+3.9b-1.2=1.8a-0.4b-1.2. So the answer will be A.
Lena [83]4 years ago
6 0
The correct answer is choice C
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let X = {a,b,c}, Y = {a,c,b}, Z = {a,b,b,c,c,c}. what are the elements of X, Y, and Z? how are X,Y, and Z related?
zhannawk [14.2K]

They're equal.

X=Y=Z

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mario62 [17]
First is B, since 1 and 3 are corresponding angles, they must be equal

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7 0
3 years ago
PLSSS ANSWER!!!!!!!!!!!!
Brums [2.3K]

Look at the picture.


The formula of an area of a triangle:


A_\Delta=\dfrac{1}{2}ab\sin\alpha


In the equilateral triangle, the measures of all angles are the same and equal to 60°.


Therefore your answer is:


\dfrac{1}{2}aa\sin(60^o)=\dfrac{1}{2}a^2\sin(60^o)

5 0
3 years ago
Suppose we have two bags with the numbers. Each bag has a total of 100 numbers. In the first bag there are 31 lucky numbers, in
attashe74 [19]

Answer:

There should be at most 24 lucky numbers in the third bag.

Step-by-step explanation:

Initially, there are 200 numbers. Two bags with 100 each. There are 31+18 = 49 lucky numbers. So there is a 49/200 = 0.245 probability that a randomly selected number from a random bag is the lucky number.

Now with 300 numbers, we want this probability to be lower than 24.5%. So we should solve the following rule of three:

200 - 49

300 - x

200x = 300*49

x = 1.5*49

x = 73.5

With the third bag, the probability will be the same if 73.5-49 = 24.5 lucky numbers are added. So there should be at most 24 lucky numbers in the third bag.

3 0
4 years ago
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