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erastovalidia [21]
4 years ago
15

Ellen Saver went to her bank. She had a balance of $2,447.67 in her savings account. She withdrew $231.49 and the teller credite

d her account with $36.61. What is her new balance?
$2,179.57
$2,252.79
$2,642.77
$2,715.77
Mathematics
2 answers:
riadik2000 [5.3K]4 years ago
6 0

Answer:

The new balance of her saving account is $ 2252.79

Step-by-step explanation:

Given : Ellen Saver went to her bank. She had a balance of $2,447.67 in her savings account. She withdrew $231.49 and the teller credited her account with $36.61.

We have to determine the new account balance.

Since inital balance is $ 2,447.67

ans she withdraw $ 231.49 that is taken ouu so we subtract from inital balance.

thus, balance after withdraw is (2447.67 - 231.49) = $ 2216.18

Now, the teller credited the account with $ 36.61 that is $ 36.61 is added to the account.

So, new balance after credit $ 36.61 is $(2216.18 + 36.61) = $ 2252.79

Thus, the new balance of her saving account is $ 2252.79

Zielflug [23.3K]4 years ago
5 0
Given:

Beginning Balance:    2,447.67
Less: Withdrawal      <u>      231.49</u>
Total                               2,216.18   
Add: Credit to acct    <u>         36.61</u>
Ending Balance    <u>       2,252.79

</u>The new balance is $2,252.79<u>
</u>
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jack wants to paint his walls. two walls are 12 ft by 8 ft and two walls are 10 ft by 8 ft. what is the area to be painted? if o
Ksivusya [100]

Answer:

352 ft (squared)  , he will need 12 paint cans

Step-by-step explanation:

Two 12 by 8ft walls = 192 ft in area, Two 10 by 8ft walls = 160 ft in Area, that equals 352 ft total, 352/30=11.73 repeated, round up to 12

4 0
2 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
3 years ago
10 + (2 x 3)2 ÷ 4 × 1 over 2 to the power of 3
Zielflug [23.3K]

Answer:

1.4375

Step-by-step explanation:

\frac{10 + (2 x 3)^{2} / (4)(1)}{2^{3}} \\

\frac{10 + (6)^{2} /4}{8} \\

\frac{10 + 36 / 4}{8} \\

\frac{46 /4}{8} \\ = \frac{11.5}{8} \\

7 0
2 years ago
How do you do this? This will be helpful with steps so i can understand this!
beks73 [17]
That looks very hard, keep trying with the steps so yeah
7 0
3 years ago
Every month, Tracie writes a check for
lisov135 [29]

She can pay the loan 18 months.

Step-by-step explanation:

Given,

Tracie has to pay $ 25 each month to pay the loan.

She has $ 450 in her account to pay the loan.

To find the number of months she can pay the loan.

We will apply the <u>unitary method</u>.

$ 25 she can pay in 1 month

$ 1 she will pay in \frac{1}{25} month

$ 450 she will pay in \frac{1}{25} × 450 months.

= \frac{450}{25}

= 18 months

6 0
3 years ago
Read 2 more answers
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