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erastovalidia [21]
3 years ago
15

Ellen Saver went to her bank. She had a balance of $2,447.67 in her savings account. She withdrew $231.49 and the teller credite

d her account with $36.61. What is her new balance?
$2,179.57
$2,252.79
$2,642.77
$2,715.77
Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0

Answer:

The new balance of her saving account is $ 2252.79

Step-by-step explanation:

Given : Ellen Saver went to her bank. She had a balance of $2,447.67 in her savings account. She withdrew $231.49 and the teller credited her account with $36.61.

We have to determine the new account balance.

Since inital balance is $ 2,447.67

ans she withdraw $ 231.49 that is taken ouu so we subtract from inital balance.

thus, balance after withdraw is (2447.67 - 231.49) = $ 2216.18

Now, the teller credited the account with $ 36.61 that is $ 36.61 is added to the account.

So, new balance after credit $ 36.61 is $(2216.18 + 36.61) = $ 2252.79

Thus, the new balance of her saving account is $ 2252.79

Zielflug [23.3K]3 years ago
5 0
Given:

Beginning Balance:    2,447.67
Less: Withdrawal      <u>      231.49</u>
Total                               2,216.18   
Add: Credit to acct    <u>         36.61</u>
Ending Balance    <u>       2,252.79

</u>The new balance is $2,252.79<u>
</u>
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If f(x) = x3 – x2 – 3, which of the following is equal to g(x) = f(2 – x)?
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Answer:

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======================================

Work Shown:

f(x) = x^3 - x^2 - 3

f(x) = (x)^3 - (x)^2 - 3

f(2-x) = (2-x)^3 - (2-x)^2 - 3 ................ see note 1 (below)

f(2-x) = (2-x)(2-x)^2 - (2-x)^2 - 3 ........... see note 2

f(2-x) = (2-x)(4-4x+x^2) - (4-4x+x^2) - 3 ..... see note 3

f(2-x) = -x^3+6x^2-12x+8 - (4-4x+x^2) - 3 ..... see note 4

f(2-x) = -x^3+6x^2-12x+8 - 4+4x-x^2 - 3 ....... see note 5

f(2-x) = -x^3+5x^2-8x+1

----------

note1: I replaced every copy of x with 2-x. Be careful to use parenthesis so that you go from x^3 to (2-x)^3, same for the x^2 term as well.

note2: The (2-x)^3 is like y^3 with y = 2-x. We can break up y^3 into y*y^2, so that means (2-x)^3 = (2-x)(2-x)^2

note3: (2-x)^2 expands out into 4-4x+x^2 as shown in figure 1 (attached image below). I used the box method for this and for note 4 as well. Each inner box or cell is the result of multiplying the outside terms. Example: in row1, column1 we have 2 times 2 = 4. You could use the FOIL rule or distribution property, but the box method is ideal so you don't lose track of terms.

note4: (2-x)(4-4x+x^2) turns into -x^3+6x^2-12x+8 when expanding everything out. See figure 2 (attached image below). Same story as note 3, but it's a bit more complicated.

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_____

<em>Comment on the problem</em>

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Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:

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