Question

Find the distance between the radical form (3,9) and (0,2)

Answer 1

Answer:

The distance between these two points is $\sqrt{58}$

Step-by-step explanation:

Step 1:  Find the distance using the distance formula

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Plug in 0 for $x_2$, 3 for $x_1$, 2 for $y_2$, 9 for $y_1$

$d = \sqrt{(0-3)^2+(2-9)^2}$

$d = \sqrt{(-3)^2+(-7)^2}$

$d=\sqrt{9+49}$

$d=\sqrt{58}$

Answer:  The distance between these two points is $\sqrt{58}$

Answer 2

Hey there!

$\large\boxed{\sqrt{58}}$

Use the pythagorean theorem:

a² + b² = c²

a will be rise and b will be run.

Distance between 9 and 2 is 7.

Distance between 3 and 0 is 3.

Plug those into the equation.

7² + 3² = c²

Square.

49 + 9 = c²

Add.

58 = c²

Square root both sides.

√58 = c

This is the distance in radical form.

Hope this helps!