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Tomtit [17]
3 years ago
5

1.

Mathematics
1 answer:
ratelena [41]3 years ago
7 0
Amount Financed: $2,650
Finance Charge: $484.69
Number of Payments: 36

(Finance Charge)/(Amount Financed)*100$=($484.69)/($2,650)*100$
(Finance Charge)/(Amount Financed)*100$=(0.1829)*100$
(Finance Charge)/(Amount Financed)*100$=$18.29

In the row of number of Payments 36, we look for:
(Finance Charge)/(Amount Financed)*100$=$18.29, and we see to which annual porcentage rate it corresponds in the first row

Answer: 11.25% 

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Ray Of Light [21]
It would be 82 2/3 since 1/3 minis 2/3 would equal -1/3 you subtract that from 83 and get 82 2/3
6 0
3 years ago
Read 2 more answers
One leg of a right triangle is 28 inches longer than the other leg, and the hypotenuse is 52 inches. Find the lengths of the leg
katovenus [111]

Step-by-step explanation:

Let x represent the missing sides measurement.

x+x+28=52

combine like terms

2x + 28 = 52

subtract 28 from both sides

2x + 28 = 52

     - 28  - 28

2x = 24

divide both sides by 2

x = 12

plug it back in

one leg is 12 inches

the other leg is 40 inches

7 0
2 years ago
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Answer:

90°

Step-by-step explanation:

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6 0
2 years ago
From experience, an airline knows that only 80% of the passengers booked for a certain flight actually show up. If 9 passengers
Olenka [21]

Answer:  0.74

Step-by-step explanation:

Given : The probability that the passengers booked for a certain flight actually show up : p=0.80

The number of passengers are randomly selected : n= 9

Binomial probability formula to find the probability of getting success in x trial :-

P(x)=^nC_xp^x(1-p)^{n-x}

Then , the probability that more than 6 of them show up will be :-

P(x>6)=P(7)+P(8)+P(9)\\\\=^9C_7(0.8)^7(0.2)^{2}+^9C_8(0.8)^8(0.2)^{1}+^9C_9(0.8)^9(0.2)^{0}\\\\=\dfrac{9!}{7!(9-7)!}(0.8)^7(0.2)^{2}+(9)(0.8)^8(0.2)+(1)(0.8)^9\approx0.3020+0.3020+0.1342=0.7382\approx0.74

Hence, the probability that more than 6 of them show up = 0.74

7 0
3 years ago
4.) The time X (minutes) for a lab assistant to prepare the equipment for a certain experiment is believed to have a uniform dis
Jet001 [13]

Answer:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

Step-by-step explanation:

For this case we define the following random variable X= (minutes) for a lab assistant to prepare the equipment for a certain experiment , and the distribution for X is given by:

X \sim Unif (a= 20, b =50)

The cumulative distribution function is given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

The expected value is given by:

E(X) = \frac{a+b}{2} = \frac{20+50}{2}=35

And we want to find the following probability:

P(35-2 < X 35+2) = P(33< X< 37)

And we can find this probability on this way:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

8 0
3 years ago
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