Add the like terms. So I'll add the variables. 8x+6x is 14x. Now add whole numbers. 30+10 is 40. Our new expression we'll be 14x+40=180. Subtract 40 from 180. 180-40=140. Now we have the expression 14x=140. 140 divided by 14 is 10. So x is 10.
We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
I'll give you a pdf so you can see it yourself and the correct answer is -32b - 32b
I the answer To You Problem Is C
M =0 if you put it in y= and hit 2nd graph and go down to the 0 there is a 1 with means m =0 (ti-84+ caculater)