1) slope is 6 and y-intercept is ( 0,5) y = mx + b, m = 6, b = 5 y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 ) First find the slope: m = (3-6)/(6-3) = -3/3 = -1 y = -x + b Plug in one of the given points (x,y) and find b 6 = -3 + b 9 = b <span> y = -x + 9</span> a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c where c is a constant number. y = 7 y=-3x+3x intercept: set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept: set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept: Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y
Answer:
2 and 3
Step-by-step explanation:
9/4=2.25
By using Euler's notation, we will see that:
z^7 = 78,125*e^(-i*4.48)
<h3>
How to get z^7?</h3>
We know that:
z = 4 - 3i
Remember that for a complex number:
w = a + bi
In Euler's notation, we can write this as:
w = √(a^2 + b^2)*e^(i*Atan(b/a))
Then, for z, we will get:
z = √(4^2 + (-3)^2)*e^(i*Atan(-3/4))
z = 5*e^(-i*0.64)
Now, if we apply an exponent of 7 to this number, we will get:
z^7 = ( 5*e^(-i*0.64))^7
z^7 = 5^7*e^(-i*7*0.64) = 78,125*e^(-i*4.48)
If you want to learn more about complex numbers, you can read:
brainly.com/question/10662770
Answer: Yes it is possible
Here's an example
Original set = {1,2,3,5,7,11}
Subset A = {1,2,3}
Subset B = {3,5,7}
The number 3 is in both subsets A and B.
{1,2,3} is a subset of {1,2,3,5,7,11} since 1,2, and 3 are part of the original set. Similar reasoning applies to subset B as well.
Something like {1,2,9} is not a subset because 9 is not found in the original set.
Answer:
Option D 
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
